Answer:
The variable, y is 11°
Step-by-step explanation:
The given parameters are;
in triangle ΔABC; 
in triangle ΔFGH;
Segment 
= 14 Segment 
= 14
Segment 
= 27 Segment 
= 19
Segment 
= 19 Segment 
= 2·y + 5
∡A = 32° ∡G = 32°
∡A = ∠BAC which is the angle formed by segments = 14 and = 19
Therefore, segment = 27, is the segment opposite to ∡A = 32°
Similarly, ∡G = ∠FGH which is the angle formed by segments = 14 and = 19
Therefore, segment = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;
≅ by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∴ = = 27° y definition of congruency
= 2·y + 5 = 27° by transitive property
∴ 2·y + 5 = 27°
2·y = 27° - 5° = 22°
y = 22°/2 = 11°
The variable, y = 11°
Using it's concept, it is found that the range of the function 
is given by:
all real numbers greater than 0.
<h3>What is the range of a function?</h3>
It is the set that contains all possible output values for the function.
In this problem, the function is:
For <u>exponential functions without vertical shifts</u>, as is the case in this problem, the range is given by:
all real numbers greater than 0.
More can be learned about the range of a function at brainly.com/question/10891721
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Answer:
475767u5yttuyy
Step-by-step explanation:
phobrovicodibfofiffivonf
