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Fiesta28 [93]
3 years ago
13

Given the following diagram, enter the required information.

Mathematics
2 answers:
devlian [24]3 years ago
8 0
CXB = 40 degrees

I am not positive but from what I have looked up this is the answer.
vitfil [10]3 years ago
3 0

we have

m∠DXB=70\°\ 15'\ 12''

m∠DXC=30\°\ 30'\ 20''

we know that

m∠DXB=m∠DXC+m∠CXB

so

m∠CXB=m∠DXB-m∠DXC

remember that

1\°=60'

1'=60''

so

m∠DXB=70\°\ 15'\ 12''

convert one grade to minutes

m∠DXB=69\°\ 75'\ 12''

convert one minute to seconds

m∠DXB=69\°\ 74'\ 72''

Find the value of m∠CXB

m∠CXB=(69\°\ 74'\ 72'')-(30\°\ 30'\ 20'')=39\°\ 44'\ 52''

therefore

<u>the answer is</u>

the measure of angle CXB is equal to 39\°\ 44'\ 52''

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Evaluate the function. h(n)=n with the power of 3 -4 find h(-2)
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Step-by-step explanation:

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3 years ago
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BartSMP [9]

Answer:

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0.285 x 100 = 28.5

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7 0
3 years ago
<img src="https://tex.z-dn.net/?f=n%20-%205%20%5Cleqslant%205n%20-%201" id="TexFormula1" title="n - 5 \leqslant 5n - 1" alt="n -
ANTONII [103]
Hello there!

n - 5 ≤ 5n - 1

Solve for n

Let's start by subtracting 5n from both sides

n - 5 - 5n ≤ 5n - 5n - 1

n - 5 - 5n ≤ -1

We need to transfer -5 on the other side, we can do that by adding 5 on both sides

n - 5 - 5n + 5 ≤ -1 + 5

n - 5n ≤ -4

-4n ≤ -4

Finally divide both sides by -4

-4n/-4 ≤ -4/-4

n ≥ -1   (This is the answer)!

Do you know why I changed the sign?


 A lot of students failed to remember that rules, which is:
When you are solving an inequality, if you divide both sides by a negative sign, you MUST change the symbol as well. If it was this <, it will change to this >. Got it? Cool!



I hope the steps are clear to understand. If you have questions, feel free to let me know...

As always, I am here to help!
7 0
3 years ago
#4 home do I find which one it is?
lina2011 [118]
\bf \begin{array}{lllll}&#10;solutions&graphs&slopes\\&#10;----&----&----\\&#10;\textit{exactly one}&&#10;\begin{array}{llll}&#10;\textit{the two lines intersect}\\&#10;\textit{at one point}&#10;\end{array}&\textit{different slopes}\\\\&#10;infinitely\quad many&&#10;\begin{array}{llll}&#10;\textit{the two lines coincide}\\&#10;\textit{one is right on top}\\&#10;\textit{ of the other}&#10;\end{array}&&#10;\begin{array}{llll}&#10;\textit{equal slopes}\\&#10;\textit{equal y-intercepts}&#10;\end{array}&#10;\end{array}

\bf \textit{no solution}\qquad\quad &\textit{lines are parallel} \qquad &&#10;\begin{array}{llll}&#10;\textit{equal slopes}\\&#10;\textit{different y-intercepts}&#10;\end{array}&#10;\end{array}

for example, let's look at the first set

y+3x =5   or  y = -3x+ 5
and               y = -3x + 2
                    y =  m  + b

the slopes are equal, the y-intercepts differ
that means, they're just parallel lines, no solution
8 0
4 years ago
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