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2 years ago

6

I kjejlkhjjkwejhtj what is 6 3/4+y=?

2 answers:

Snezhnost [94]2 years ago

5 0

6.75. nnansnsnsn in ajajanskaks

labwork [276]2 years ago

3 0

Answer:
27/4 + y
_______

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How do you solve the equation:

Molodets [167]

Copy and paste the answer on quizlet

5 0

2 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago

6 is what percent of 8?

kvasek [131]

6 is 75% of 8. 6/8 can be simplified to 3/4, which is easier to see as 75%.

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2 years ago

Which number is the exponent in 10 by the power of 5

almond37 [142]

The exponent in the equation is the 5.

5 0

2 years ago

Find the upper limit for the zeros of the function P(x)=4x^4+8x^3-7x^2-21x-9

pishuonlain [190]

Answer:

OPTION B - 2

Step-by-step explanation:

What is the upper limit for the zeros of the function P(x) = 4x^4 + 8x^3 - 7x^2 - 21x - 9. Ans: 2 is an upper limit. Use synthetic division. and the remainder are all positive, 2 is an upper limit.

3 0

2 years ago