9514 1404 393
Answer:
(B) 4
Step-by-step explanation:
Consider the units column. The only sum of 3 and a single digit that will end in 1 is the sum ...
3 + 8 = 11
This tells you A = 8, so the top number is 1983, and the middle number is B78.
Considering the first two columns, we know that 83 +78 = 161, so there must be a carry of 1 into the third column. That makes it have the sum ...
1 + 9 + B = <something ending in 4>
We know the something cannot be 04 or 24, so must be 14. Then ...
10 + B = 14 ⇒ B = 4
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So, the whole sum is ...
1983 +478 = 2461
and the letter values are ...
Answer:
Below
Step-by-step explanation:
● cos O = 2/3
We khow that:
● cos^2(O) + sin^2(O) =1
So : sin^2 (O)= 1-cos^2(O)
● sin^2(O) = 1 -(2/3)^2 = 1-4/9 = 9/9-4/9 = 5/9
● sin O = √(5)/3 or sin O = -√(5)/3
So we deduce that tan O will have two values since we don't khow the size of O.
■■■■■■■■■■■■■■■■■■■■■■■■■
●Tan (O) = sin(O)/cos(O)
● tan (O) = (√(5)/3)÷(2/3) or tan(O) = (-√(5)/3)÷(2/3)
● tan (O) = √(5)/2 or tan(O) = -√(5)/2
The answer is 7
7^ ⁴ = 49
Answer:
I don't now this but you should do pemdas that really helped me
Step-by-step explanation:
The first step is perthansies then exponents and then multiplication then division and last addition and subtraction that should give you your answer.
I think the answer is 60
idk
