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mina [271]
4 years ago
6

A hexagon can be divided into how many triangles by drawing all of the diagonals from one vertex?

Mathematics
2 answers:
ki77a [65]4 years ago
4 0
A. 4 triangles are formed

Readme [11.4K]4 years ago
4 0

Answer:

4 triangles are formed.

Step-by-step explanation:

Given a hexagon that can be divided into triangles by drawing all of the diagonals from one vertex.

we have to find the number of triangles formed.

As shown in attachment if we a diagonals from one vertex then only 3 diagonals are drawn which results into 4 triangles.

Hence, 4 triangles are formed by drawing all of the diagonals from one vertex.

Hence, option A is correct.

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Mamont248 [21]
The area of a paralellogram is bh

each dimention is multiplied by n
b turns to bn
h turns to hn

bh turns to (bn)(hn) or bnhn or bhn²

expression is bhnn or bhn² or bhn^2 (depends if the program will let you enter the exponent)
6 0
3 years ago
I don’t understand this problem
ikadub [295]

Hello! the answer is c

First of all let's eliminate the answers that do not make sense. For A. numbers are NOT irrational because they are a fraction. Numbers are also not irrational because they are a repeating number. C and D are both correct as fractions and terminating decimals are both rational numbers.

34/3≈11.33333333

By using a certain formula you can convert repeating decimals to a fraction. But most people know that .3333333 is 1/3. This gives us 11 1/3 as our answer. So what does it match? It is not a terminating decimal. It repeats but can be written as a fraction. Therefore our answer is C) Rational, because it is a fraction.

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4 0
4 years ago
Which of the following statements is true for the logistic differential equation?
solong [7]

Answer:

All of the above

Step-by-step explanation:

dy/dt = y/3 (18 − y)

0 = y/3 (18 − y)

y = 0 or 18

d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)

d²y/dt² = dy/dt (-y/3 + 6 − y/3)

d²y/dt² = dy/dt (6 − 2y/3)

d²y/dt² = y/3 (18 − y) (6 − 2y/3)

0 = y/3 (18 − y) (6 − 2y/3)

y = 0, 9, 18

y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.

y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.

8 0
3 years ago
If line segment BH = 3, line segment BF = 10, line segment GH= 2, find HD 15 11 10.5 ?
pav-90 [236]

HD = 10.5

Step-by-step explanation:

Given BH = 3, GH = 2, BF = 10

Step 1: To find HF:

HF = BF – BH

HF = 10 – 3

HF = 7

Step 2: To find HD:

We know that if two chords intersects inside a circle, the product of the lengths of the segments of one chord equals the product of the lengths of the segments of the other chord.

⇒ GH × HD = BH × HF

⇒ 2 × HD = 3 × 7

⇒ HD = 10.5

Hence, the value of HD = 10.5.

5 0
3 years ago
Read 2 more answers
Solve for u .<br><br> -24 = u ÷ 6 <br><br> u = ?
Ainat [17]
-24=u/6 just times 6 to both sides -24*6=-144 rewrite
-144=u
Hope this helps have a nice day
5 0
3 years ago
Read 2 more answers
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