A hexagon can be divided into how many triangles by drawing all of the diagonals from one vertex?
2 answers:
Answer:
4 triangles are formed.
Step-by-step explanation:
Given a hexagon that can be divided into triangles by drawing all of the diagonals from one vertex.
we have to find the number of triangles formed.
As shown in attachment if we a diagonals from one vertex then only 3 diagonals are drawn which results into 4 triangles.
Hence, 4 triangles are formed by drawing all of the diagonals from one vertex.
Hence, option A is correct.
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Solution:
We have to prove that ,
△ABC ~ △Z Y X Using SAS.
It is given that , ∠X ≅ ∠C .
You must keep in mind when two triangles are similar by S A S
1. The included side between the angle should be Proportional.
2. We have to prove that ,
△ABC ~ △Z Y X Using SAS.
It is given that , ∠B ≅ ∠Y .
The included side between the given angle should be Proportional.
3. We have to prove that ,
△ABC ~ △Z Y X Using SSS.
The three sides of two triangles must be Proportional.