A hexagon can be divided into how many triangles by drawing all of the diagonals from one vertex?
2 answers:
Answer:
4 triangles are formed.
Step-by-step explanation:
Given a hexagon that can be divided into triangles by drawing all of the diagonals from one vertex.
we have to find the number of triangles formed.
As shown in attachment if we a diagonals from one vertex then only 3 diagonals are drawn which results into 4 triangles.
Hence, 4 triangles are formed by drawing all of the diagonals from one vertex.
Hence, option A is correct.
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The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:
Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
Learn more about adiabatic expansion on:
#SPJ1
Answer:
- greater area: A
- no, B has the greater volume
Step-by-step explanation:
The relevant area and volume formulas are ...
A = 2(LW +H(L +W))
V = LWH
When there are multiple instances of the calculations to be done, it is convenient to let a spreadsheet do them. The results are attached.
Figure A has the larger area.
Figure B has the larger volume.
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<em>Additional comment</em>
The more "cube-like" the prism is, the less area it will have for the same volume. Here, package B is more "cube-like" than package A. (The ratio of largest-to-smallest dimensions is smaller for package B.)
