All categories

3 years ago

What are the coordinates of the image of point R(3,-4) after a reflection over the line x=5?

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

4 0

Answer:

R' is ( 7 , -4 )

Step-by-step explanation:

( 3 , -4 ) reflected over x = 5

Since the line x = 5 is vertical we'll need to add to the x coordinate of point R.

( 3 , -4 ) is 2 units away from x = 5 so we'll need to add 2 units to 5 and we get

( 7 , -4 ) is R'

vekshin13 years ago

3 0

Answer:

(7,-4)

if x=5 then imagine a new vertical line on 5

(3,-4) is two spaces left of 5, so to reflect if you would move it two spaces to the right of 5

You might be interested in

Carla brought $240 to spend on gifts for her family she found a identical statues at the gift shop she had $72 leftover. how muc

Stells [14]

Each one cost $21.

$240-$72=$168

$168/8=$21

8 0

3 years ago

Read 2 more answers

Samantha had 500 jars of slime 30% green 25% clear and 15% purple the rest of the jars of slime were blue how many jars were blu

natima [27]

Answer:

150

Step-by-step explanation:

100% represents 500 jars

Subtract the sum of the percentage of other jars for percent of blue jars

100 - (30 + 25 + 15) = 100 - 70 = 30%

That is 30% of the jars are blue

Calculate 30% of 500 to obtain number of blue jars

30% = $\frac{30}{100}$ = 0.3, hence

number of blue jars = 0. 3 × 500 = 150

8 0

3 years ago

I've been at this for half an hour Help

Mazyrski [523]

Answer:

$(-\frac{3}{4})^1^0$

Step-by-step explanation:

$((-\frac{3}{4} )^5)^2$

==> simplify using the power of a power rule

$(-\frac{3}{4})^1^0$

Power of a power rule

$(x^a)^b=x^a^*^b$

explanation of rule : multiply the two powers and keep the base the same

4 0

2 years ago

I need this please help me

rewona [7]

Function a has a rate of change of 2 and function b has a rate of change of .75. So function a has a greater rate of change.

4 0

3 years ago

Suppose a culture of bacteria begins with 5000 cells and dies by 30% each year. Write an equation that represents this situation

Mazyrski [523]

Answer:

$A(t)=5000(0.7)^t$

Step-by-step explanation:

The problem presented is one in which the population of the bacteria depreciates by a decay factor r every year.

Since it is a decay problem, we use the model:

$A(t)=P(1-r)^t$

Initial Population, P=5000

Decay Rate,r=30%=0.3

t=time interval

Therefore, the equation that represents this situation is:

$A(t)=5000(1-0.3)^t$

$A(t)=5000(0.7)^t$

4 0

3 years ago