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alexandr1967 [171]
3 years ago
5

7. What is the cardinality of each of the following sets?

Mathematics
1 answer:
zysi [14]3 years ago
8 0

Answer:  

The cardinality of set (a) is 0,

the cardinality of set (b) is 1

and

the cardinality of set (c) is 3.

Step-by-step explanation:  We are given to find the cardinality of each of the following sets :

(a) { }.

(b) { { } }.

(c) {a, {a}, {a, {a}} }.

We know that

CARDINALITY of a set is the number of elements present in the set.

(a) The given set is A = { }.

The set A is an empty set, so it does not contain any element. Hence, the cardinality of the set A is 0.

(b) The given set is B = { { } }.

The set is B is singleton set, contains only one element (that is empty set). So, the cardinality of the set B is 1.

(c) The given set is C = {a, {a}, {a, {a}} }.

The set C has three elements, a, the set {a} and the set {a, {a}}. So,  the the cardinality of set C is 3.

Thus,

the cardinality of set (a) is 0,

the cardinality of set (b) is 1

and

the cardinality of set (c) is 3.

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andreyandreev [35.5K]

Answer:

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Step-by-step explanation:

14. The sum of the opposite angle of the quadrilateral is 180degrees. Hence;

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3 years ago
Compute the value of the discriminant and give the number of real solutions of the quadratic equation. -9x to the second power-6
Step2247 [10]
Answer:
discriminant=0
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Step-by-step explanation:

Given the equation:
-9x^2-6x-1=0
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Let b: coefficient of x
Let c: constant
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discriminant= (-6)^2 - 4(-9)(-1)
= 36 - 36 = 0
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Here we got discriminant=0 so the quadratic equation has 1 real root.
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