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sweet-ann [11.9K]

2 years ago

13

A medication is available in 1000mcg per mL. How much is needed for a 0.8mg dose?

1 answer:

Setler [38]2 years ago

8 0

Answer:

5 doses of medication and 1000ml

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Can someone help me with this problem

SVETLANKA909090 [29]

3x + 14 = 143

3x = 129

X = 43

5 0

2 years ago

Read 2 more answers

The diagram below shows the dimensions of a triangular park built in a new housing development. Two side lengths and one angle m

evablogger [386]

ANSWER

$x = 50.5 \degree$

EXPLANATION

We use the sine rule for solving triangles.

This is given by the formula,

$\frac{ \sin(A) }{a} = \frac{ \sin(B) }{b} = \frac{ \sin(C) }{c}$

From the triangle,

$\frac{ \sin(x) }{60} = \frac{ \sin(40) }{50}$

We multiply both sides of the equation by 60 to get,

$sin(x) = \frac{ 60\sin(40 \degree) }{50}$

$sin(x) = 0.7713$

We solve for x to obtain,

$x = arcsin(0.7713)$

$x = 50.475$

To the nearest tenth, we round to one decimal place to get,

$x = 50.5 \degree$

7 0

3 years ago

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

1 year ago

Which statement below is correct

Lynna [10]

The correct answer is A

4 0

2 years ago

John ran the 200 meter dash and clocked the following times: 24.4, 27.2, 30.6, 24.1, 29.9, and 27.0. What was John's average tim

nasty-shy [4]

Answer: 27.2

Step-by-step explanation: add up the values then divide by the amount of values (6)

7 0

2 years ago