Which best describes the diagram?

Nookie1986 [14]

First work out the parenthesis:

9x⁴y⁴ / 3y²

Then get rid of the denominator using 9/3=3 and y⁴/y² = y²

3x⁴y² is the simplest form.

6 0

3 years ago

Question 19

atroni [7]

Answer:

When Jon determined A(12), it means he must have found the amount in the account after 12 years. i.e. the amount when t = 12 years.

Hence, option (A) is true.

Step-by-step explanation:

BACKGROUND KNOWLEDGE ABOUT EXPONENTIAL GROWTH

We know that an exponential increase in Math can be termed as the rapid increase of an amount by percentage over a certain period of time.

It can be expressed using the formula

y = a (1+b)ˣ

here

y represents the final amount

a represents the original amount

b represents the growth factor

x represents the time that has passed

Now, let is us map our problem because it indicates the same concept.

SOLVING THE QUESTION

Given the function

$A\left(t\right)=2000\left(1+0.0412\right)^{12t}$

Here

A(t) represents the final amount

2000 represents the original amount

0.0412 represents the growth rate

t represents the number of years

Thus,

When Jon determined A(12), it means he must have found the amount in the account after 12 years. i.e. the amount when t = 12 years.

Hence, option (A) is true.

8 0

3 years ago

According to records, the amount of precipitation in a certain city on a November day has a mean of inches, with a standard devi

Mekhanik [1.2K]

Answer:

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is mean amount of inches of rain and $\sigma$ is the standard deviation.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean $\mu$ , standard deviation $\sigma$

n days:

This means that $s = \frac{\sigma}{\sqrt{n}}$

Applying the Central Limit Theorem to the z-score formula.

$Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

What is the probability that the mean daily precipitation will be of X inches or less for a random sample of November days?

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is mean amount of inches of rain and $\sigma$ is the standard deviation.

5 0

3 years ago

John and Andrew have £3.40 between them. John has £1.20 more than Andrew. John has £u and Andrew £v

Dahasolnce [82]

In the given question, there are several information's of immense importance and they can be used to find the necessary answers. It is already given that John and Andrew have 3.40 pound together. It is also given that John has 1.20 pound more than Andrew. It is also assumed that John has"u" pound and Andrew has "v" pounds.
Then we can write the two equations as
u + v = 3.40
u = v + 1.20
To find the values of u and v, we can replace the u in the first equation with the value of u in the second equation. Then
u + v = 3.40
(v + 1.20) + v = 3.40
2v + 1.20 = 3.40
2v = 3.40 - 1.20
2v = 2.2
v = 2.2/2
= 1.1
Now we replace the value of v in the first equation to find the value of u.
u + v = 3.40
u + 1.1 = 3.40
u = 3.40 - 1.1
u = 2.3

6 0

3 years ago

Find the GCF of 44 and 66

NISA [10]

The factors of 44 are: 1, 2, 4, 11, 22, 44

The factors of 66 are: 1, 2, 3, 6, 11, 22, 33, 66

Then the greatest common factor is 22.

7 0

3 years ago

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