There isn't enough info to prove the triangles to be congruent or not. So we can't say for sure either way.
We have angle CAD = angle ACB given by the arc markings, and we know that AC = AC due to the reflexive theorem. However we are missing one third piece of information.
That third piece of info could be....
- AD = BC which allows us to use SAS
- angle ACD = angle CAB which allows us to use ASA
- angle ABC = angle CDA which allows us to use AAS (slight variation of ASA)
Since we don't know any of those three facts, we simply don't have enough information.
side note: If AB = CD, then this leads to SSA which is not a valid congruence theorem. If we had two congruent sides, the angle must be between the two sides, which is what AD = BC allows.
Answer:
about 10 without a remainder of 4
Step-by-step explanation:
So, add up the number and divide by how many number you have (definition of mean). 8 + 25 + 9 + 10 + 11 + 1 all divide by 6 (since there are 6 numbers)
8 + 25 + 9 + 10 + 11 + 1 is 64.
64/6 is about 10 without a remainder of 4
Answer:

Step-by-step explanation:
On the right side of the = multiply -4 through

add 28a and add 4 to both sides


divide both sides by 22

It already is in simplest form. In mixed fraction, it would be 9 1/7
The law of logarithms is
㏒ₓᵃ =n and a=x^n
we have ㏒₃ 9=2
3 is the base