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pantera1 [17]
3 years ago
10

What is 14*6/1 hurry

Mathematics
1 answer:
shtirl [24]3 years ago
4 0
Easy all you do is <span>14<span>(6/1)</span></span><span>=<span><span>(14/1)</span><span>(6/1)</span></span></span><span>=<span><span>(14)(6)</span><span>(1)(1)</span></span></span><span>=84</span>

          
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PLEASE HELP I WILL GIVE BRAINLIEST Complete the frequency table: Method of Travel to School Walk/Bike Bus Car Row totals Under a
frozen [14]

Answer:

11%

Step-by-step explanation:

1. Fill out the table with the correct numbers.

2. After you fillout the numbers, you should notice that under the column car and in the first row, there should be the number 18.

3. We know the total number of students under the age of 15 is 165.

4. To find the percent:

       18/165 * 100

               = 11%

3 0
3 years ago
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Which of the following is most likely the next step in the series?
dem82 [27]
A.
This is because in each circle the lines increase by one, so from the triangle (3 lines) to the rectangle (4 lines) it only makes sense to put a pentagon (5 lines)
6 0
3 years ago
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Which two expressions are
Oxana [17]

Answer:

9(2p-18) and 2(9p-18)

Step-by-step explanation:

6 0
3 years ago
System of Equations <br> Need help<br> Trig
Yanka [14]

Looks like the system is

\begin{cases}-2x+y+6z=1\\3x+2y+5z=16\\7x+3y-4z=11\end{cases}

We can eliminate y by taking

(3x+2y+5z)-2(-2x+y+6z)=16-2(1)

\implies3x+2y+5z+4x-2y-12z=16-2

\implies7x-7z=14

\implies x-z=2

so that z=x-2, and

(7x+3y-4z)-3(-2x+y+6z)=11-3(1)

\implies7x+3y-4z+6x-3y-18z=11-3

\implies13x-22z=8

Substitute z=x-2 into this last equation and solve for x:

13x-22(x-2)=8

\implies13x-22x+44=8

\implies-9x=-36

\implies x=4

Then

z=x-2

\implies z=4-2

\implies z=2

Plug these values into any one of the original equation to solve for y:

-2x+y+6z=1

\implies-2(4)+y+6(2)=1

\implies-8+y+12=1

\implies y=-3

Hence the solution is x = 4, y = -3, and z = 2.

6 0
3 years ago
Shark Inc. has determined that demand for its newest netbook model is given by lnq−3lnp+0.004p=7ln⁡q−3ln⁡p+0.004p=7, where q is
olga2289 [7]
  <span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q: 

(1/q)(dq/dp) − 3/p + 0.003 = 0 
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So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p. 

b) The revenue is pq. 
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1: 

3 − 0.003p = −1 
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p = 4/0.003 = 4000/3 = 1333.33</span>
8 0
3 years ago
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