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zheka24 [161]
3 years ago
13

I need help on this question plz make it fast

Mathematics
1 answer:
krek1111 [17]3 years ago
5 0
It’s i, II, and iii I do believe.
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3. The following sequence shows the number of pushups Kendall did each week, starting with her first week of exercising: 6, 18,
Alona [7]

{{{ THE BOLDED CHARACTERS SHOULD BE SMALL. }}}

SEQUENCE: 6, 18, 54, 162

18/6 = 3

54/18 = 3

162/54 = 3

then, r (common ratio) = 3

_________________________________________

RECURSIVE RULE: r = 3

an = a(n - 1) × r       [formula]

ANSWER: an = a(n - 1) × 3

_________________________________________

ITERIATIVE RULE: r = 3, a1 = 6

an = a1 × r^(n - 1)       [formula] [ ^(n-1) is an exponent]

ANSWER: an = 6 × 3^(n - 1)

4 0
2 years ago
A.756<br> b.936<br> c.1,008<br> d.1,080<br> HELLLPPPPP
luda_lava [24]

Answer:

936 is the correct option

6 0
3 years ago
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If sinx=2cosx then, what is the value of sin2x?
Travka [436]
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         tan(x) = 2
tan⁻¹[tan(x)] = tan⁻¹(2)
                x ≈ 63.4

sin(2x) = sin[2(63.4)]
sin(2x) = sin(126.8)
sin(2x) ≈ 0.801
3 0
3 years ago
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How many feet are in 2 miles 300 feet?
Stells [14]
I believe the answer would be 10,860 my friend :) good luck with your problem, and have a great day
3 0
2 years ago
In ΔBCD, the measure of ∠D=90°, the measure of ∠B=71°, and DB = 67 feet. Find the length of BC to the nearest tenth of a foot.
PSYCHO15rus [73]

Answer:

in triangle BCD

relationship between base and hypotenuse is given by cos angle

cos 71=b/h

cos71=BD/BC

cos71=67/x

x=67/cos71=205.8ft.

the length of BC to the nearest tenth of a foot is 206ft.

8 0
3 years ago
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