Answer:
- This might help a liitle its kind of like the question you are asking.
- You might not want to give people 5 points for a long question because most of them might not awnser.
Step-by-step explanation:
The Prove that two non-zero vectors are collinear if and only if one vector is a scalar multiple of the other is given below.
<h3>What are the proves?</h3>
1. To know collinear vectors:
∧ ⁻a ║ ⁻a
If ⁻b = ∧ ⁻a
then |⁻b| = |∧ ⁻a|
So one can say that line ⁻b and ⁻a are collinear.
2. If ⁻a and ⁻b are collinear
Assuming |b| length is 'μ' times of |⁻a |
Then | 'μ' ⁻a| = | 'μ' ⁻a|
So ⁻b = 'μ' ⁻a
Learn more about vectors from
brainly.com/question/25705666
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Answer:
SOLUTION STEPS
6
8
5
+−6
3
1
Multiply 6 and 8 to get 48.
8
48+5
−
3
6×3+1
Add 48 and 5 to get 53.
8
53
−
3
6×3+1
Multiply 6 and 3 to get 18.
8
53
−
3
18+1
Add 18 and 1 to get 19.
8
53
−
3
19
Least common multiple of 8 and 3 is 24. Convert
8
53
and
3
19
to fractions with denominator 24.
24
159
−
24
152
Since
24
159
and
24
152
have the same denominator, subtract them by subtracting their numerators.
24
159−152
Subtract 152 from 159 to get 7.
24
7
Step-by-step explanation:
Smaller because off the number value and places.
Answer:
2/9
2 to 9
Step-by-step explanation:
