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o-na [289]
3 years ago
5

Which word or phrase that best describes the probability??

Mathematics
1 answer:
Llana [10]3 years ago
5 0
100% = Certain (no matter what.. it's going to happen)
75/100 = Likely (has a high chance of happening)
5/10 = Equally likely (can happen, or might not)
1/4 = Unlikely (might not happen)
0.0 = Impossible 

hope this helps
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6 soccer balls for $150
eduard

the cost of one soccer ball is 150/6 or 25 dollars.

4 0
3 years ago
Read 2 more answers
Someone help me with this I will make you brain
hram777 [196]

Step-by-step explanation:

let's look at the full numbers under the square roots when bringing the external factors back in :

sqrt(9×9×2) - sqrt(3×3×7) + sqrt(8) - sqrt(28)

and let's present these numbers as the product of their basic prime factors

sqrt(3×3×3×3×2) - sqrt(3×3×7) + sqrt(2×2×2) - sqrt(2×2×7)

now we see that we have 2 pairs of square roots : 1 pair ends with a factor of 2, and one pair with a factor of 7.

let's combine these

sqrt (3×3×3×3×2) + sqrt(2×2×2) - sqrt(3×3×7) - sqrt (2×2×7)

and now we move the factors of 2 and 7 back out in front (of course, we need to apply the square root on these factors) :

9×sqrt(2) + 2×sqrt(2) - 3×sqrt(7) - 2×sqrt(7) =

= (9+2)×sqrt(2) - (3+2)×sqrt(7) = 11×sqrt(2) - 5×sqrt(7)

and that is the first answer option.

5 0
3 years ago
Lea buys 6 model cars that each cost $15 she also buys 4 bottles of paint that each cost $11 how much does lea spends on model c
MissTica
Times the price of the model cars to the amount bought.

$15×6= 90.

Lea paid 90 dollars for the model cars.

Now, multiply the price of the paint to the amount bought.

$11×4= 44.

Lea paid 44 dollars for the paint.

Add both together. 90+44= 134.

Therefore, Lea paid $134 for the model cars and paint all together.

hope this helps!
8 0
3 years ago
Stella needs fencing for the perimeter of a
Crazy boy [7]

Answer:

\boxed{Fencing \: need \: to \: buy \: for \: the \: entire \: perimeter = \frac{40}{3}  \: yards}

Step-by-step explanation:

Length of rectangular garden (l) = 16 feet

Width of rectangular garden (w) = 4 feet

3 \: feet = 1 \: yard \\  \\   1 \: feet =  \frac{1}{3}  \: yard

\\ =  > Perimeter \: of \: rectangular \: garden = 2(l + w) \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  = 2(16 + 4) \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:   \: = 2 \times 20 \\  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:   \:  = 40 \: feets \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:   \:  =40 \times  \frac{1}{3}  \: yards \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:   \:  = \frac{40}{3}  \: yards

4 0
3 years ago
Working together to palms can drain a certain pool in three hours if it takes the older pump nine hours to drain the pool by its
andreyandreev [35.5K]

Answer:

It would take the newer pump 4.5 hours to drain the pool

Step-by-step explanation:

Let's investigate first what is the fraction of the job done in the unit of time (hour in this case) by each pump if the work individually:

older pump: if it takes it 9 hours to complete the job, it does \frac{1}{9} of the job in one hour.

newer pump: we don't know how long it takes (this is our unknown) so we call it "x hours". Therefore, in the unit of time (in one hour) it would have completed \frac{1}{x} of the total job.

both pumps together: since it takes both 3 hours to complete the job, in one hour they do \frac{1}{3} of the job.

Now, we can write the following equation about fractions of the job done:

<em>The fraction of the job done by the older pump plus the fraction of the job done by the newer pump in one hour should total the fraction of the job done when they work together.</em> That is in mathematical terms:

\frac{1}{9} +\frac{1}{x} =\frac{1}{3}

and solving for x:

\frac{1}{9} +\frac{1}{x} =\frac{1}{3} \\x+9=3x\\2x=9\\x=\frac{9}{2} \,\,hours\\x = 4.5\,\,hours

4 0
3 years ago
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