(a) getting the difference of outputs of any two inputs that are 1 unit apart, we have the following:
-3 – (-11) = 8
5 – (-3) = 8
13 – 5 = 8
21 – 13 = 8
29 – 21 = 8
37 – 29 = 8
45 – 37 = 8
53 – 45 = 8
(b) getting the difference of outputs of any two inputs that are 2 units apart, we have the following:
5 – (-11) = 16
13 – (-3) = 16
21 – 5 = 16
29 – 13 = 16
37 – 21 = 16
45 – 29 = 16
53 – 37 = 16
(c) getting the difference of outputs of any two inputs that are 3 units apart, we have the following:
13 – (-11) = 24
21 – (-3) = 24
29 – 5 = 24
37 – 13 = 24
45 – 21 = 24
53 – 29 = 24
(d) To get the ratio of the required problem, first we divide the first difference of outputs by one input interval, that is
8÷1=8
Next, we divide the second differences of outputs by two input intervals, that is
16÷2=8
Lastly, we divide the third differences of outputs by three input intervals, that is
24÷3=8
Notice that each ratio have the same result which is 8. This means that whatever the number input intervals are, between two outputs is 8 times apart.
Answer:
x = 8
Step-by-step explanation:
combine like terms:
18x + 36 = 180
18x = 180-36
18x = 144
x = 144/18
x = 8
Step-by-step explanation:
-x+2y=-6
x-2y=6
x=2y+6
substitute in 2x-3y=11 gives us 2(2y+6)-3y=11
4y+12-3y=11
y=-1
-x+2(-1)=-6
-x=-4
x=4
Answer:
Step-by-step explanation:
Write a list of all possible outcomes
1-2
1-3
1-4
2-1
2-3
2-4
3-1
3-2
3-4
4-1
4-2
4-3
There are 12 possible outcomes. How many of them have totals of 6 or 7
I count 4
So the probability is 4/12 = 1/3, just as you said.
Is there an easier way?
You might be able to get the 12 easier.
You have 4 choices for the first number and 3 for the second.
P(12) = 4*3 = 12
Getting 6 or 7 might be somewhat trickier.
4 and 3 make seven. That gives two ways 4-3 and 3-4
4 and 2 make six. That gives 2 more ways 4-2 and 2-4
That's all that's possible.
answer: 4 ways make success. The total number of ways is 12.
Can you provide a picture ?? or some sort of context
