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3 years ago

Janine inflated a ball to a radius of 18 cm and another ball to a radius of 12 cm.

Mathematics

2 answers:

nekit [7.7K]3 years ago

6 0

Answer:since your are looking for the volume of the ball, the answer would be 17182.08

Step-by-step explanation:

Sladkaya [172]3 years ago

3 0

Volume of a ball = (4/3)πr³

When r = 18cm, V = (4/3)×3.14×18³ =24416.64 cm³
When r = 12cm, V = (4/3)×3.14×12³ =7234.56 cm³
Difference = 24416.64 - 7234.56 = 17182.08 cm³

the volume of air in the larger ball is <span>17182.08 cm³ greater than smaller ball </span>

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You are training your dog to catch a frisbee. You are playing in a large field, and you are standing next to your dog when you t

sergey [27]

The paths will cross when the coordinates are (1,9) and (4, 15).

<h3>What is a model?</h3>

A model is a representation of reality. Now we have that the path of the frisbee is y = -x² + 7x + 3 while the path of the dog is y = 2x + 7.

The both paths will cross when;

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2 years ago

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Taya2010 [7]

$\boxed { \boxed { a_n = a_1 + d(n - 1)}}$

$a_{14} = -33 , a_{15} = 9,$

$a_{14} = a_1 + d(14 - 1) = -33$
$a_1 + 13d = -33$

$a_{15} = a_1 + d(15 - 1) = 9$
$a_1 + 14d = 9$

So the two equations:
$a_1 + 13d = -33$ ----------------- ( 1 )
$a_1 + 14d = 9$ ----------------- ( 2 )

(2) - (1) :
$d = 42$ ----------------- (Sub into 1)

$a_1 + 13(42) = -33$
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$a_1 = -33 - 546$
$a_1 = -579$

$\boxed { \boxed { a_n = -578 + 42(n - 1)}}$

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3 years ago