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ra1l [238]
3 years ago
11

The y-intercept of a line is the value of the y- coordinate where the line crosses the ________

Mathematics
1 answer:
Shalnov [3]3 years ago
3 0

y-axis

That last sentence though, I died reading that.

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Hope this helps :)

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You work at a job where your average monthly earnings are $682 with a standard deviation of $49. Your mean monthly expenses are
Pavel [41]

Answer:

S = I-E.

We can find the expected value of S and we got:

E(S) = E(I-E) = E(I) -E(E)= 682-211=471

And that represent the mean of the amount of money into your savings account each month

And now we can find the variance of the random variable S like this:

Var(S) = Var(I-E) = Var(I) +Var(E) - 2Cov(I,E)

And since we know that Cov (I,E) =0 then we have:

Var(S) = Var(I) + Var(E) = 49^2 + 16^2 = 2657

And then the deviation would be:

Sd(S) = \sqrt{2657}= 51.546

And that represent the standard deviation of the amount of money you put in your savings account each month

Step-by-step explanation:

Let I the random variable that represent the income for each month and we know:

E(I) = 682, \sigma_I = 49

Let E the random variable that represent the monthly expenses for each month and we know:

E(E)= 211, \sigma_E = 16

And for this case we know that the random variables I and E are independent, so then Cov(I, E) = 0

We can define the random variable S representing the amount that we can save each month and we can define S = I-E.

We can find the expected value of S and we got:

E(S) = E(I-E) = E(I) -E(E)= 682-211=471

And that represent the mean of the amount of money into your savings account each month

And now we can find the variance of the random variable S like this:

Var(S) = Var(I-E) = Var(I) +Var(E) - 2Cov(I,E)

And since we know that Cov (I,E) =0 then we have:

Var(S) = Var(I) + Var(E) = 49^2 + 16^2 = 2657

And then the deviation would be:

Sd(S) = \sqrt{2657}= 51.546

And that represent the standard deviation of the amount of money you put in your savings account each month

3 0
3 years ago
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