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blsea [12.9K]
3 years ago
15

Suppose x coins are tossed. Write an expression to represent the number of possible outcomes.

Mathematics
2 answers:
Amanda [17]3 years ago
8 0

Answer:

= 2^x

Step-by-step explanation:

One coin tossed:

Total outcomes = {H,T} =2 = 2^1

Two coins tossed:

Total outcomes :{HH,HT,TH,TT} = 4= 2^2

Three coins are tossed:

Total outcomes : {HHH,HHT, HTT,TTT,THH,TTH,THT,HTH} =8  = 2^3

So, 1 coin tossed = 2^1

      2 coins tossed = 2^2

      3 coins tossed = 2^3

Continuing in this manner ..

      x coins tossed = 2^x

Thus an expression to represent the number of possible outcomes when x coins are tossed : 2^x

Gnom [1K]3 years ago
3 0
We know that one coin has 2 sides, this makes it so the expression is 2 multiplied by x, or 2x
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You toss a coin a randomly selecte a number from 0 to 9. What is the probability of getting tails and selecting a 9?
In-s [12.5K]
First lets find the probability of landing tails. Because there is 1 way to get tails and 2 possible outcomes, the probability is 1/2.

Now, lets find the probability of selecting a 9. Since this includes 0, there are 10 possible outcomes and 1 way to get a 9, so the probability is 1/10.

To find them combined, multiply:

1/2 * 1/10
1/20
0.05

Hope this helps!


4 0
3 years ago
The producer of a certain bottling equipment claims that the variance of all its filled bottles is .027 or less. A sample of 30
o-na [289]

Answer:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

b. between .025 and .05

Step-by-step explanation:

Previous concepts and notation

The chi-square test is used to check if the standard deviation of a population is equal to a specified value. We can conduct the test "two-sided test or a one-sided test".

\bar X represent the sample mean

n = 30 sample size

s= 0.2 represent the sample deviation

\sigma_o =\sqrt{0.027}=0.164 the value that we want to test

p_v represent the p value for the test

t represent the statistic

\alpha= significance level

State the null and alternative hypothesis

On this case we want to check if the population standard deviation is less than 0.027, so the system of hypothesis are:

H0: \sigma \leq 0.027

H1: \sigma >0.027

In order to check the hypothesis we need to calculate the statistic given by the following formula:

t=(n-1) [\frac{s}{\sigma_o}]^2

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

t=(30-1) [\frac{0.2}{0.164}]^2 =42.963

What is the approximate p-value of the test?

The degrees of freedom are given by:

df=n-1= 30-1=29

For this case since we have a right tailed test the p value is given by:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

And the best option would be:

b. between .025 and .05

6 0
3 years ago
Julio practiced his trumpet on each 6 days during a week. What is the mean of minutes Julio practiced over these 6 days.
Novay_Z [31]
21+30+39+43+58+67 = 258.  
258/6 = 43

43 minutes
4 0
3 years ago
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ruslelena [56]

542,591,806.5

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Answer:

24

Step-by-step explanation:

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