Select the Expressions that are equivalent to -2(4-3x)+(5x-2) PLZ help do tommorrow

Nelson and Jamie both want to buy a $250 bicycle.

adelina 88 [10]

Nelson needs to save $114 and Jamie needs $108.

3 0

2 years ago

Read 2 more answers

4. In a cricket match a batsman hits of boundary 6 time out of 30 balls find the probability

antiseptic1488 [7]

Answer:

here

Step-by-step explanation:

We have been given that, in a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays and we have to find the probability of not hitting boundary. So, the probability of hitting boundary⇒Number of boundaries hitTotal number of balls=630=15.

7 0

2 years ago

Find each of the following for

KATRIN_1 [288]

<h2>Answer:</h2>

(a)

$f(x+ h)=8x+8h+3$

(b)

$f(x+ h)-f(x)=8h$

(c)

$\dfrac{f(x+ h)-f(x)}{h}=8$

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as :

$f(x)=8x+3$

(a)

$f(x+ h)$

We will substitute (x+h) in place of x in the function f(x) as follows:

$f(x+h)=8(x+h)+3\\\\i.e.\\\\f(x+h)=8x+8h+3$

(b)

$f(x+ h)-f(x)$

Now on subtracting the f(x+h) obtained in part (a) with the function f(x) we have:

$f(x+h)-f(x)=8x+8h+3-(8x+3)\\\\i.e.\\\\f(x+h)-f(x)=8x+8h+3-8x-3\\\\i.e.\\\\f(x+h)-f(x)=8h$

(c)

$\dfrac{f(x+ h)-f(x)}{h}$

In this part we will divide the numerator expression which is obtained in part (b) by h to get:

$\dfrac{f(x+ h)-f(x)}{h}=\dfrac{8h}{h}\\\\i.e.\\\\\dfrac{f(x+h)-f(x)}{h}=8$

5 0

3 years ago

Suppose PR = 54, solve for QR<br> 4x-1<br> 3x-1<br> P<br> R

Svet_ta [14]

Answer:

$QR = 23$

Step-by-step explanation:

P, A, and R are collinear.

PR = 54

$PQ = 4x - 1$

$QR = 3x - 1$

To solve for the numerical length of PR, let's generate an equation to find the value of x.

According to the segment addition postulate:

$PQ + QR = PR$

$(4x - 1) + (3x - 1) = 54$ (substitution)

Solve for x

$4x - 1 + 3x - 1 = 54$

Combine like terms

$4x + 3x - 1 - 1 = 54$

$7x - 2 = 54$

Add 2 to both sides

$7x - 2 + 2 = 54 + 2$

$7x = 56$

Divide both sides by 7

$\frac{7x}{7} = \frac{56}{7}$

$x = 8$

$QR = 3x - 1$

Plug in the value of x into the equation

$QR = 3(8) - 1 = 24 - 1$

$QR = 23$

5 0

3 years ago

A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is

Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

$\Delta s = s_2-s_1$

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

$\Delta x = x_2-x_1$

So we can use the given points $P1:(x_1,y_2) \text{ and } P_2: (x_2,y_2)$ on the displacement formula

$\Delta x = 15-4\\\Delta x = 11$

In the same manner we can look at the y components of those points to find the vertical displacement

$\Delta y = 17-8\\\Delta y =9$

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

$\tan(\theta) = \cfrac{\Delta y}{\Delta x}$

Solving for the angle we get

$\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)$

Replacing values

$\theta = \tan^{-1}\left(\cfrac{9}{11}\right)$

Which give us

$\theta = 39.3^\circ$

So the projection angle is 39.3 degrees.

7 0

3 years ago