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Anni [7]
3 years ago
7

What is the rounding number for 5503

Mathematics
1 answer:
fredd [130]3 years ago
4 0
If u round 5503 you will round it to 5500
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The expression 0.15(x-350) would be the proper equation.

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Midpoint Between Two Given Points
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Answer:

(1, -7)

Step-by-step explanation:

the difference between -4 & 6 is 10 so you add 5 (half) to -4 or subtract from 6, this gives you 1

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2 years ago
Compute the multifactor productivity measure for each of the weeks shown for production of chocolate bars. What do the productiv
liq [111]

Answer:

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

Step-by-step explanation:

Computation for the multifactor productivity measure for each of the weeks shown for production of chocolate bars.

Using this formula

Week Multifactor productivity measure = (Output / Total Cost)

Where:

Output represent Quantity produced

Total cost represent Labor cost + Material cost + Overhead

Let plug in the formula

Week 1= 30,000/(40*12*6)+[(40*12*6)1.5]+(450*6)

Week 1 =30,000/(2,880)+(2,880*1.5)+2,700

Week 1 =30,000/(2,880+4,320+2,700)

Week 1=30,000/9,900

Week 1 =3.03

Week 2= 33,600/(40*12*7)+[(40*12*7)1.5]+(470*6)

Week 2 =33,600/(3,360)+(3,360*1.5)+2,820

Week 2=33,600/(3,360+5,040+2,820)

Week 2=33,600/11,220

Week 2 =2.99

Week 3= 32,200/(40*12*7)+[(40*12*7)1.5]+(460*6)

Week 3 =32,200/(3,360)+(3,360*1.5)+2,760

Week 3=32,200/(3,360+5,040+2,760)

Week 3=32,200/11,160

Week 3=2.9

Week 4= 35,400/(40*12*8)+[(40*12*8)1.5]+(480*6)

Week 4 =35,400/(3,840)+(3,840*1.5)+2,880

Week 4=35,400/(3,840+5,760+2,880)

Week 4=35,400/12,480

Week 4=2.83

Therefore the multifactor productivity measure for each of the weeks shown for production of chocolate bars is :

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

4 0
2 years ago
What is the area of a triangle with base 18 meters and height<br>6 meters?​
mash [69]

Answer:

27 meters

Step-by-step explanation:

a=1/2bh

a=1/2(18)(6)

a=27

6 0
3 years ago
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