I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?
In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0 and (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.
So you're final answer should be y = i and 9
So, if you add 25 and 52 you get 75. All angles of a triangle need to add up to 180. the angle c will be around 105 degrees i assume
Answer: 19
Step-by-step explanation:
3^3=27, 27-7=20, 20·5=100, 100/10=10.
1+3=4, 4+6=10, 10+9=19, 19-10=9.
10+9=19.
I'm not 100% sure if I'm doing it the right way, but I think the answer is the factorial of the number of letters divided by the factorials of the number of elements of each kind of element (in this case, the same letters)
9!/1!4!1!2!1!
= 9 · 8 · 7 · 6 · 5 · 4!/4!2!
= 9 · 8 · 7 · 6 · 5/2
= 9 · 4 · 7 · 6 · 5
= 63 · 120
= 7,560 permutations
