Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
150 minus 30 equals 120 but i did 150/30 and got 5
You will need 6 coins of 5
and 2 coins of 1
hope it helps
=) = )
Answer:
9/10
Step-by-step explanation:
90%
We can distribute the negative to get 8 + 6i + 2 - 7i, and we can simplify that to get 10 - i.
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Hope this helps!