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jek_recluse [69]
3 years ago
5

If the simple interest on $5000 for 5 years is $1500 then what is the interest rate?​

Mathematics
2 answers:
hjlf3 years ago
8 0

15%?

Its 15 because it just is because I am big brain.

Its the thingy because 5 and 5 and another 5 plus 1500 = 15%

No idea how I came up with 15%

SashulF [63]3 years ago
4 0

Answer:

6%

Step-by-step explanation:

Simple interest:  A = P(1 + rt)

Solve for r: r = (1/t)((A/P) - 1)

Given:

A = $1500 + $5000 = $6500

P = $5000

t = 5 yrs

r = (1/5)((6500/5000) - 1)

= (1/5)(0.3)

= 0.06

0.06 = 6%

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A) 17 <br> b) 15<br> c) 18<br> d) 16<br> ^ Which one ?
Mekhanik [1.2K]

Answer:

15

Step-by-step explanation:

if one side is 9, another is C, based on the angle tilt would have to be 15.

Hope its helps.

4 0
3 years ago
Help pls I'll give 25 points
RideAnS [48]

Answer:

\text{C. }60

Step-by-step explanation:

<u>Question from image</u>:

"The digits 1, 2, 3, 4, and 5 can be formed to arrange 120 different numbers. How many of these numbers will have the digits 1 and 2 in increasing order? For example, 14352 and 51234 are two such numbers."

Let's start by taking a look with the number 1. There are four possible places 1 could be, because there needs to be space for the 2 after it.

Checkmarks mark where the 1 can be, the <em>x</em> marks where it cannot be.

\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{X}

Let's start with the first position:

\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are four places the 2 can be. For each of these four places, we can arrange the remaining 3 digits in 3!=6 ways. Therefore, there are 4\cdot 6=\boxed{24} possible numbers when 1 is the first digit of the number.

Continue this process with the remaining possible positions for 1.

Second position:

\underline{X}\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are three places the 2 can be, since the 2 must be behind the 1. For each of these three places, the remaining 3 digits can be arranged in 3!=6 ways. Therefore, there are 3\cdot 6=\boxed{18} possible numbers when 1 is the second digit of the number.

The pattern continues. Next there will be 2 places to place the 2. For each of these, there are 3!=6 ways to rearrange the remaining 3 digits for a total of 2\cdot 6=\boxed{12} possible numbers when 1 is the third digit of the number.

Lastly, when 1 is the fourth digit of the number, there is only 1 place the 2 can be. For this one place, there are still 3!=6 ways to rearrange the remaining three numbers. Therefore, there are 1\cdot 6=\boxed{6} possible numbers when 1 is the fourth digit of the number.

Thus, there are 24+18+12+6=\boxed{60} numbers that will have the digits 1 and 2 in increasing order, from a set of 120 five-digit numbers created by the digits 1 through 5, where no digit may be repeated.

5 0
3 years ago
In a 30-60-90 triangle, how many sides do you need to know in order to determine the remaining sides?
podryga [215]
You need to know one side.
3 0
3 years ago
Read 2 more answers
Round 5,382,619 to the nearest 1,000
Naddik [55]
5,383,000

Hope this helped

6 0
3 years ago
HELP PLEASE!!!!! PLEASE EXPLAIN WHEN GIVING THE ANSWER!!!! GIVING BRAINLIEST TO THE BEST EXPLANATION!!!!
atroni [7]

Answer:Simplificando

5 (2j + 3 + j) = 0

Reordene os termos:

5 (3 + 2j + j) = 0

Combine termos semelhantes: 2j + j = 3j

5 (3 + 3j) = 0

(3 * 5 + 3j * 5) = 0

(15 + 15j) = 0

Resolvendo

15 + 15j = 0

a verdadeira questão é por que o vizinho de Sarah quer dentes de tubarão

Step-by-step explanation:

Mova todos os termos contendo j para a esquerda, todos os outros termos para a direita.

Adicione '-15' a cada lado da equação.

15 + -15 + 15j = 0 + -15

Combine termos semelhantes: 15 + -15 = 0

0 + 15j = 0 + -15

15j = 0 + -15

Combine termos semelhantes: 0 + -15 = -15

15j = -15

Divida cada lado por '15'.

j = -1

Simplificando

j = -1

Tubarão ou cação é um tipo de peixe de esqueleto cartilaginoso e um corpo hidrodinâmico (com exceção dos Squatiniformes, Hexanchiformes e Orectolobiformes)

4 0
3 years ago
Read 2 more answers
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