1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jek_recluse [69]
3 years ago
5

If the simple interest on $5000 for 5 years is $1500 then what is the interest rate?​

Mathematics
2 answers:
hjlf3 years ago
8 0

15%?

Its 15 because it just is because I am big brain.

Its the thingy because 5 and 5 and another 5 plus 1500 = 15%

No idea how I came up with 15%

SashulF [63]3 years ago
4 0

Answer:

6%

Step-by-step explanation:

Simple interest:  A = P(1 + rt)

Solve for r: r = (1/t)((A/P) - 1)

Given:

A = $1500 + $5000 = $6500

P = $5000

t = 5 yrs

r = (1/5)((6500/5000) - 1)

= (1/5)(0.3)

= 0.06

0.06 = 6%

You might be interested in
4.5x-7=20 i need help whats the answer
Dmitry [639]
Your answer will be 6. 
7 0
3 years ago
Read 2 more answers
4 divided by -3 as a simplified fraction
tensa zangetsu [6.8K]

Answer:

The answer is -4/3 or -1 1/3

4 0
3 years ago
Read 2 more answers
Bad gums may mean a bad heart. Researchers discovered that 80% of people who have su ered a heart attack had periodontal disease
saul85 [17]

Answer:

0.069 = 6.9% probability that he or she will have a heart attack

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Does not have periodontal disease

Event B: Has a heart attack.

Probability of not having a periodontal disease:

100 - 80 = 20% of 10%(had a heart attack).

30% of 100-10 = 90%(did not have a heart attack). So

P(A) = 0.2*0.1 + 0.3*0.9 = 0.29

Intersection of A and B:

Not having the disease, suffering a heart attack, so 20% of 10%.

P(A cap B) = 0.2*0.1 = 0.02

What is the probability that he or she will have a heart attack?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.02}{0.29} = 0.069

0.069 = 6.9% probability that he or she will have a heart attack

6 0
3 years ago
Use the conversions given below to change 83 kg into stones.
eduard

83 kg converted to stones is 13 stones.

Step-by-step explanation:

Given,

We have to convert 83 kg to stones.

As it is given,

1 kg = 2.2 pounds

83 kg = 2.2*83 pounds

83 kg = 182.6 pounds

Now,

14 pounds = 1 stone

1 pound = \frac{1}{14}\ stones

182.6 pounds = \frac{1}{14}*182.6

182.6 pounds = 13.04 stones

Rounding to one dp

182.6 pounds = 13.0 stones

83 kg converted to stones is 13 stones.

Keywords: converting units, division

Learn more about division at:

  • brainly.com/question/10677255
  • brainly.com/question/10689103

#LearnwithBrainly

4 0
3 years ago
Berta worked to solve a system of equations. 4x + y = –5 x – y = –5 Step 1: ??? Step 2: x = –2 Step 3: 4(–2) + y = –5 Step 4: –8
Lemur [1.5K]
5x= -10
I hope I could help.

7 0
3 years ago
Read 2 more answers
Other questions:
  • PLEASE HELP!!!!!!!!
    5·1 answer
  • Find the horizontal asymptote
    5·1 answer
  • Helpppppppppppppppppppp
    13·2 answers
  • How many cupcakes can I make with 16 cups of batter into each cupcake
    9·2 answers
  • If the 1st and 10th terms of geometric sequence are 4 and 100, find the nth term of the sequence
    11·1 answer
  • Find the value of x in the triangle shown below.
    10·1 answer
  • Find an ordered pair (x, y) that is a solution to the equation. -x+4y= 5​
    9·1 answer
  • Jimmy's Bakery sold 950 donuts last week. This week, the number of donuts sold increased 12%. How many more donuts were sold thi
    7·1 answer
  • In a group of 52 cards, how many different groups of 5 cards can you be dealt?
    14·1 answer
  • 10/27 (3/8 divided by 5/24
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!