Ask question

Ask question

All categories

3 years ago

7

Cupro-nickel coins are minted by mixing copper and nichel in the ratio 4:1

1 answer:

Softa [21]3 years ago

8 0

Copper: Nickel = 4:1

a) How much copper needed for 20 kg nickel
   C:N = 4: 1
   C:20 = 4:1

C/20 = 4/1 Cross Multiply
C*1 = 4*20
C = 80

80kg Copper would be needed.

b) How much Nickel would be needed for 20 kg of Copper
   C:N = 4: 1
   20:N = 4:1

20/N = 4/1 Cross Multiply
4*N = 1*20
4N = 20 Divide both sides by N.

N = 20/4 = 5

5kg Nickel would be needed.

You might be interested in

Two number cubes are rolled.

yaroslaw [1]

Answer:

1/4

Step-by-step explanation:

Assuming the number cube is a six-faced die, you have

1 <u>2</u> 3 <u>4</u> 5 <u>6</u>

three odd numbers, and three even numbers. Therefore, the chance of it landing on an odd number or even number is 3/6, which equals 1/2. <em>That means you have a 50% chance to get an odd number, or an even number.</em>

<em />

So, you have two die. Both have a 50/50 chance of getting an even or odd number. So what's the chance of one landing on an odd number, and the other landing on an even number?

You would have a 25% chance for an <u>even</u> and then an <u>even</u> number

You would have a 25% chance for an <u>odd</u> and then an <u>odd</u> number

You would have a 25% chance for an <u>even</u> and then an <u>odd</u> number

You would have a 25% chance for an <u>odd</u> and then an <u>even</u> number.

25% as a simplified fraction is 1/4. Therefore, 1/4 is your answer.

8 0

2 years ago

Read 2 more answers

What’s the place value of 9 in 987,164

Art [367]

Hello

The place value is 9 hundred thousand or 900,000

Hope this helps
Plz mark me as Brainliest

6 0

3 years ago

Read 2 more answers

Graph the equation on the cordinate plane y = -2x

ruslelena [56]

Answer:

Step-by-step explanation:

7 0

3 years ago

Four students had the following amounts of money in their pockets: $3.14, $.67, $2.45, and $1.14. How much money did they have t

Butoxors [25]

A. $7.40
Adding $3.14 to $0.67 equals $3.81
You then could add $2.45 to $3.81 and get $6.26
Finally you add $1.14 to $6.26 and get $7.40

7 0

2 years ago

Read 2 more answers

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

4 0

3 years ago