Given:


Multiply both sides by 3/2, we get

Cancel out the common multiples, we get



The solution of the given equation is

or
Answer:
well i think the answer is B.
The x² term will be C(5,2)x²·2³ = 80x².
The coefficient is 80.
_____
C(n, k) = n!/(k!·(n-k)!)
C(5, 2) = 5·4/(2·1) = 10
Answer:
21. 98 cents
Gabby placed in 4th.
Step-by-step explanation:
Assuming Steven is paying, 51+45+2=98 cents.
Unproportional. 60/10=6
90/20=4.5
120/30=4
150/40=3.75