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igomit [66]
4 years ago
10

What is the area of the figure?

Mathematics
1 answer:
Korolek [52]4 years ago
6 0

Answer:

  96 m²

Step-by-step explanation:

The figure is a trapezoid with bases of length 10 m and 22 m, and height 6 m. Putting these numbers into the formula for area of a trapezoid gives ...

  A = (1/2)(b1 +b2)h

  = (1/2)(10 m +22 m)(6 m) = 96 m²

The area of the figure is 96 m².

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swat32

Answer:

Step-by-step explanation:

ore energy entered the Earth system than exited due to the greenhouse effect, solar energy trapping systems like solar panel, etc.

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3 years ago
What is the first step when rewriting y = -4x2 + 2x - 7 in the form y = a(x - h) + K?
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Answer:

h = -b/2a

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to find the vertex (h,k)

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4 years ago
In the Midpoint Rule for triple integrals we use a triple Riemann sum to approximate a triple integral over a box B, where f(x,
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To approximate the volume with 8 boxes, we have to split up the interval of integration for each variable into 2 subintervals, [0, 1] and [1, 2]. Each box will have midpoint m_{i,j,k} that is one of all the possible 3-tuples with coordinates either 1/2 or 3/2. That is, we're sampling f(x,y,z)=\cos(xyz) at the 8 points,

(1/2, 1/2, 1/2)

(1/2, 1/2, 3/2)

(1/2, 3/2, 1/2)

(3/2, 1/2, 1/2)

(1/2, 3/2, 3/2)

(3/2, 1/2, 3/2)

(3/2, 3/2, 1/2)

(3/2, 3/2, 3/2)

which are captured by the sequence

m_{i,j,k}=\left(\dfrac{2i-1}2,\dfrac{2j-1}2,\dfrac{2k-1}2\right)

with each of i,j,k being either 1 or 2.

Then the integral of f(x,y,z) over B is approximated by the Riemann sum,

\displaystyle\iiint_B\cos(xyz)\,\mathrm dV\approx\sum_{i=1}^2\sum_{j=1}^2\sum_{k=1}^2\cos m_{i,j,k}\left(\frac{2-0}2\right)^2

=\displaystyle\sum_{i=1}^2\sum_{j=1}^2\sum_{k=1}^2\cos\frac{(2i-1)(2j-1)(2k-1)}8

=\cos\dfrac18+3\cos\dfrac38+3\cos\dfrac98+\cos\dfrac{27}8\approx\boxed{4.104}

(compare to the actual value of about 4.159)

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