Answer:
one point
Step-by-step explanation:
A system of two linear equations will have one point in the solution set if the slopes of the lines are different.
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When the equations are written in the same form, the ratio of x-coefficient to y-coefficient is related to the slope. It will be different if there is one solution.
- ratio for first equation: 1/1 = 1
- ratio for second equation: 1/-1 = -1
These lines have <em>different slopes</em>, so there is one solution to the system of equations.
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<em>Additional comment</em>
When the equations are in slope-intercept form with the y-coefficient equal to 1, the x-coefficient is the slope.
y = mx +b . . . . . slope = m
When the equations are in standard form (as in this problem), the ratio of x- to y-coefficient is the opposite of the slope.
ax +by = c . . . . . slope = -a/b
As long as the equations are in the same form, the slopes can be compared by comparing the ratios of coefficients.
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If the slopes are the same, the lines may be either parallel (empty solution set) or coincident (infinite solution set). When the equations are in the same form with reduced coefficients, the lines will be coincident if they are the same equation.
Answer:
Correct choices are A and C
Step-by-step explanation:
Inscribed angles property: The inscribed angles subtended by the same arc are equal.
1. Angles EFH and EGH are both inscribed angles subtended by the arc EH. Therefore, these angles are congruent (option A is true).
2. Angles GHF and GEF are both inscribed angles subtended by the arc GF. Therefore, these angles are congruent (option C is true).
3. Angles EGH and FHG are interior angles of the triangle KGH and can be congruent (if triangle is isosceles) or can be not congruent (in general). Thus, option B is false.
4. Angles EFH and FHG in general are not congruent. They can be congruent only when arcs EH and FG have the same measure. In general, option D is false.
To find the length of the diagonal of a square, multiply the length of one side by the square root of 2.
so ur answer is : 11 sqrt 2...its A
Answer:
Step-by-step explanation:
Let us assume that we have n different dots on a paper. We are to connect pairwise by a line. We have to find out how many lines can be formed.
Let us prove by induction.
If there is one dot then we have no line = 1(1-1) =0
Thus n(n-1) is true for 1 dot
Let us assume that for n dots we have n(n-1) lines
Add one more point now total points are n+1.
Already the existing n points are connected by a line.
So the extra point has to be connected to each of n point
i.e. n lines should be added from the new point to the n points and again n lines from the points to the new point(Assuming lines are different if initial and final point are different)
So 2n lines would be added
So total number of lines for n+1 points
Thus true for n+1 if true for n. Already true for n =1
So proved by induction for all natural numbers n.
Answer:
12 days
Step-by-step explanation:
