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Answer:
AB = 14 and BC = 17
Step-by-step explanation:
Congruence is a property that shows an equal relation between sides or angles of a given figure or two figures.
From the question, the given conditions are;
BC = AD, AD = 17, DC = 14, and m< 1 = m<2 .
i. Considering the property of congruence of sides,
BC = 17 (∵ BC = AD and AD has been given to equal 17)
i.e BC = AD = 17
ii. Considering the property of congruent angles and sides,
AB = 14 (∵ m<1 = m<2 and DC is 14)
Therefore, AB = 14 and BC = 17.
<h2>Steps:</h2>
So firstly, we need to factor out the GCF. Since all the terms share a GCF of x, factor that out as such:
![(x)(x^2y^2-x^4+y^3-yx^2)](https://tex.z-dn.net/?f=%28x%29%28x%5E2y%5E2-x%5E4%2By%5E3-yx%5E2%29)
Next, I will be factoring by grouping. For this, factor x²y² + y³ and -x⁴ - yx². Make sure that they have the same quantity on the inside:
![(x)(y^2(x^2+y)-x^2(x^2+y))](https://tex.z-dn.net/?f=%28x%29%28y%5E2%28x%5E2%2By%29-x%5E2%28x%5E2%2By%29%29)
Now rewrite the expression as:
![(x)(y^2-x^2)(x^2+y)](https://tex.z-dn.net/?f=%28x%29%28y%5E2-x%5E2%29%28x%5E2%2By%29)
However, we can factor this expression further. Next, we will be applying the difference of squares rule, which is
. In this case:
![y^2-x^2=(y+x)(y-x)\\\\(x)(y+x)(y-x)(x^2+y)](https://tex.z-dn.net/?f=y%5E2-x%5E2%3D%28y%2Bx%29%28y-x%29%5C%5C%5C%5C%28x%29%28y%2Bx%29%28y-x%29%28x%5E2%2By%29)
<h2>Answer:</h2>
In short, the factored form of this expression is:
![(x)(y+x)(y-x)(x^2+y)](https://tex.z-dn.net/?f=%28x%29%28y%2Bx%29%28y-x%29%28x%5E2%2By%29)
Answer:
The answer is 2 6/8
Step-by-step explanation: