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diamong [38]
3 years ago
15

∠PQR and ∠SQR form a linear pair. Find the sum of their measures. ____

Mathematics
1 answer:
sdas [7]3 years ago
6 0
A linear pair means the adjacent angles form a line...meaning they equal 180 degrees
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the tax on a property with an assessed value of $64,000 is $650. Using a proportion, find the tax on a property with an assessed
AVprozaik [17]
The answer is $1200.
5 0
3 years ago
John can clean pools at a constant rate of 3/5 pools/hours. How many pools can John clean in 10 hours?
Ket [755]

Answer:

30/5=  6

Explicción:

Lo  utliplicas yl odivides ..m

7 0
3 years ago
The process standard deviation is 0.27, and the process control is set at plus or minus one standard deviation. Units with weigh
mr_godi [17]

Answer:

a) P(X

And for the other case:

tex] P(X>10.15)[/tex]

P(X>10.15)= P(Z > \frac{10.15-10}{0.15}) = P(Z>1)=1-P(Z

So then the probability of being defective P(D) is given by:

P(D) = 0.159+0.159 = 0.318

And the expected number of defective in a sample of 1000 units are:

X= 0.318*1000= 318

b) P(X

And for the other case:

tex] P(X>10.15)[/tex]

P(X>10.15)= P(Z > \frac{10.15-10}{0.05}) = P(Z>3)=1-P(Z

So then the probability of being defective P(D) is given by:

P(D) = 0.00135+0.00135 = 0.0027

And the expected number of defective in a sample of 1000 units are:

X= 0.0027*1000= 2.7

c) For this case the advantage is that we have less items that will be classified as defective

Step-by-step explanation:

Assuming this complete question: "Motorola used the normal distribution to determine the probability of defects and the number  of defects expected in a production process. Assume a production process produces  items with a mean weight of 10 ounces. Calculate the probability of a defect and the expected  number of defects for a 1000-unit production run in the following situation.

Part a

The process standard deviation is .15, and the process control is set at plus or minus  one standard deviation. Units with weights less than 9.85 or greater than 10.15 ounces  will be classified as defects."

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(10,0.15)  

Where \mu=10 and \sigma=0.15

We can calculate the probability of being defective like this:

P(X

And we can use the z score formula given by:

z=\frac{x-\mu}{\sigma}

And if we replace we got:

P(X

And for the other case:

tex] P(X>10.15)[/tex]

P(X>10.15)= P(Z > \frac{10.15-10}{0.15}) = P(Z>1)=1-P(Z

So then the probability of being defective P(D) is given by:

P(D) = 0.159+0.159 = 0.318

And the expected number of defective in a sample of 1000 units are:

X= 0.318*1000= 318

Part b

Through process design improvements, the process standard deviation can be reduced to .05. Assume the process control remains the same, with weights less than 9.85 or  greater than 10.15 ounces being classified as defects.

P(X

And for the other case:

tex] P(X>10.15)[/tex]

P(X>10.15)= P(Z > \frac{10.15-10}{0.05}) = P(Z>3)=1-P(Z

So then the probability of being defective P(D) is given by:

P(D) = 0.00135+0.00135 = 0.0027

And the expected number of defective in a sample of 1000 units are:

X= 0.0027*1000= 2.7

Part c What is the advantage of reducing process variation, thereby causing process control  limits to be at a greater number of standard deviations from the mean?

For this case the advantage is that we have less items that will be classified as defective

5 0
3 years ago
What is the surface area of the box if it is scaled up by a factor of 10? Boxes Dimensions 7in Height 6in Length 2in Width
VladimirAG [237]

Answer:

13,600 in^{2}

Step-by-step explanation:

(h = 7, l = 6, w = 2) 10

70, 60, 20

2(h × w) + 2(h × l) + 2(w × l)

= 2(70 × 20) + 2(70 × 60) + 2(20 × 60)

= 2(1400) + 2(4200) + 2(1200)

= 2800 + 8400 + 2400

= 13,600

4 0
3 years ago
ME AYUDAN?? ¨Carlos compró un automóvil nuevo por un valor de $39000. Cada año que pasa desde la compra el auto disminuye su val
MrRa [10]

Multiplica 30 por 1500

Luego resta el resultado de la multiplicación por 39000 y te da el resultado de nada

3 0
3 years ago
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