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solniwko [45]
2 years ago
8

Could someone do a step-by-step? 2x < x − 4 ≤ 3x + 8

Mathematics
1 answer:
navik [9.2K]2 years ago
4 0

Answer:

−

6

≤

x

<

−

4

Interval Notation:

[

−

6

,

−

4

)

Step-by-step explanation:

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The base of a rectangular solid is 4ft. long and 3ft. wide. What is the volume of the solid if its diagonal is sqrt of 41 ft.?
geniusboy [140]
The diagonal of the figure forms a right angle triangle with the diagonal of the base and the height of the figure.
Diagonal of base = √(3² + 4²)
= 5ft
Diagonal of solid² = Diagonal of base² + height²
height = √((√41)² + 5²)
height = 8.12 feet
Volume = width x length x height
Volume = 3 x 4 x 8.12
= 97.44 cubic feet
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3 years ago
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pav-90 [236]

Answer:

Step-by-step explanation:

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2 years ago
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How do I compare decimal numbers
Neporo4naja [7]
When comparing decimals, start in the tenths place. The decimal with the biggest value there is greater. If they are the same, move to the hundredths place and compare these values. If the values are still the same keep moving to the right until you find one that is greater or until you find that they are equal.
6 0
3 years ago
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The perimeter of a playing field for a certain sport is 174 ft. The field is a rectangle, and the length is 45 ft longer than th
Leno4ka [110]

Answer:

21 ft by 66 ft

Step-by-step explanation:

From the question,

P = 2(L+W)............... Equation 1

Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.

If the Length of the Field is 45 ft longer than the width,

L = 45+W............ Equation 2

Substitute Equation 2 into equation 1

P = 2(45+W+W)

P = 90+4W............. Equation 3

Given: P = 174 ft.

Substitute into equation 3

174 = 90+4W

4W = 174-90

4W = 84

W = 84/4

W = 21 ft.

Substituting the value of W into equation 2

L = 45+21

L = 66 ft.

Hence the dimensions of the playing field is 21 ft by 66 ft

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2 years ago
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Alexxx [7]
8 is the answer, yw have a nice day:)
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2 years ago
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