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Monica [59]
3 years ago
14

Classify the following triangle Check all that apply ?

Mathematics
2 answers:
KengaRu [80]3 years ago
8 0
It is Isosceles and an obtuse triangle. 
Gennadij [26K]3 years ago
3 0
Scalene- why? Because all three sides are different lengths and numbers.

Obtuse- why? Because the angle at the vertex formed is bigger than 90 degrees.

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You are an urban planner assessing the growth of a city. Ten years ago, the city's population was 249,583. Its current populatio
solmaris [256]
318,270-249,583=68,687\\\\\begin{array}{ccc}249,583&-&100\%\\68,687&-&p\%\end{array}\\\\cross\ multiply\\\\249,583p=68,687\cdot100\ \ \ \ /:249,583\\\\p\approx27.52\\\\Answer:\\The\ city\ grown\ over\ the\ past\ ten\ years\ at\ 27.52\%.
4 0
3 years ago
Read 2 more answers
Find the values of a and b so that the solution of the linear system is (-9,1).
Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

we can write -9 instead of x and y=1 instead of 1

so we write solution again

-9a+1b=-31

-9a-1b=-41

-18a=-72

a=4

we should write 4 instead of a

-9(4)+1b=-31

-36+b=-31

b=5

a=4

6 0
3 years ago
Can you please help me?
larisa [96]
Replace the words with what you know
(Original cost)(6%)=5.25
(Original cost)(0.06)=5.25
(original cost)=5.25/0.06=87.5
6 0
4 years ago
Read 2 more answers
??????can someone help???
ehidna [41]
The answer is C, from where the end lines go down to on the graph
8 0
3 years ago
The number of violent crimes committed in a day possesses a distribution with a mean of 2.2 crimes per day and a standard deviat
VARVARA [1.3K]

Answer:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

Step-by-step explanation:

For this case we have the following info given:

\mu = 2.2 represent the mean

\sigma = 6 represent the deviation

We select a sample size of n=100. This sample is >30 so then we can use the central limit theorem. And we want to find the distribution for the sample mean and we know that the distribution is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

6 0
3 years ago
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