Answer:
The rate at which the distance between the two cars is increasing is 30 mi/h
Step-by-step explanation:
Given;
speed of the first car, v₁ = 24 mi/h
speed of the second car, v₂ = 18 mi/h
Two hours later, the position of the cars is calculated as;
position of the first car, d₁ = 24 mi/h x 2 h = 48 mi
position of the second car, d₂ = 18 mi/h x 2 h = 36 mi
The displacement of the two car is calculated as;
displacement, d² = 48² + 36²
d² = 3600
d = √3600
d = 60 mi
The rate at which this displacement is changing = (60 mi) / (2h)
= 30 mi/h
Id say 0.187 because 0.033 times 17. then that number divided by 3
Answer:
P + B = 14130P + 150B = 1920
Step-by-step explanation:
P + B = 14130P + 150B = 1920
P = 14 - B
130(14-B) + 150 = 1920
20B = 100
B = 100/20 = 5
P = 14 - 5 = 9
