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3 years ago

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Find the midpoint of segment JP, given J(-4,6) and P(-12,-2).

1 answer:

grin007 [14]3 years ago

6 0

Answer:

The answer is

<h2>( - 8 , 2)</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

<h3> $M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )$ </h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

J(-4,6) and P(-12,-2)

The midpoint is

<h3> $M = ( \frac{ - 4 - 12}{2} , \: \frac{6 - 2}{2} ) \\ = ( - \frac{16}{2} , \: \frac{4}{2} )$ </h3>

We have the final answer as

<h3>( - 8 , 2)</h3>

Hope this helps you

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A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

vredina [299]

Answer:

C. One can be 95% confident that the true proportion of all students receiving financial aid is between 0.52 and 0.66

Step-by-step explanation:

Given that the confidence interval is a term that defines a range of values with the probability to contain a population value that has an actual degree of confidence.

This is represented in a situation where population means falls in between upper and lower intervals.

Hence, in this case, the correct interpretation is option C: One can be 95% confident that the true proportion of all students receiving financial aid is between 0.52 and 0.66

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3 years ago

Which graph represents f(x)=6cos(4πx) ?

lesya692 [45]

Answer:

The graph representing f(x)=6cos(4πx) is shown in the attached file.

Step-by-step explanation:

The graph representing f(x)=6cos(4πx) is shown in the attached file.

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3 years ago

matt rode his bike to the store by traveling 5 km east and the 3 km north. what distance (a) did he travel? and what was his dis

slamgirl [31]

A = 5 km is your distance it is how far he traveled.

b = 3 km is your displacement it's the length in which he when north.

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3 years ago

The outside temperature can be estimated based on how fast crickets chirp. At 104 chirps per minute, the temperature is 63 degre

Rasek [7]

Answer:

For 124 chirps per minute the temperature is 68 ºF.

For 68 chirps per minute the temperature is 54 ºF.

Step-by-step explanation:

Linear functions are those whose graph is a straight line. A linear function has the following form

$f(x)=b+mx$

b is the constant term or the y intercept. It is the value of the dependent variable when x = 0.

m is the coefficient of the independent variable. It is also known as the slope and gives the rate of change of the dependent variable.

We know that

At 104 chirps per minute, the temperature is 63 ºF.

At 176 chirps per minute, the temperature is 81 ºF.

This information can be converted to Cartesian coordinates (x, y). Where x = the number of chirps per minute and y = the temperature in ºF.

To find a linear function that let us find the outside temperature from how fast crickets chirp we must:

Find the slope:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{81-63}{176-104}=\frac{1}{4}$

Find the equation:

$81=\frac{1}{4}\cdot 104+b$

Solving for b

$b=81-\frac{1}{4} (176)=37$

Therefore, the linear function is

$y=\frac{1}{4} \cdot x+37$

Now, using this linear function we can know the temperature when we know the chirps per minute:

For 124 chirps per minute the temperature is:

$y=\frac{1}{4} \cdot (124)+37=68$

For 68 chirps per minute the temperature is:

$y=\frac{1}{4} \cdot (68)+37=54$

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2 years ago

Find the solution set 7x^2-9x-10=0

vitfil [10]

Answer:

x = -5/7, 2

Step-by-step explanation:

Step 1: Factor

(5x + 7)(x - 2) = 0

Step 2: Find <em>x </em>roots

5x + 7 = 0

x = -5/7

x - 2 = 0

x = 2

5 0

2 years ago

Read 2 more answers