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3 years ago

CAN SOMEONE PLEASE HELP ME WITH THIS FUNCTION PROBLEM

Mathematics

1 answer:

ycow [4]3 years ago

8 0

Answer:

Choose f(x) = 11x + 1

Step-by-step explanation:

Note that we will simply plug the value of 2 into the equation for February:

f(2) = 11(2) + 1 = 23

And plug the value of 6 into the equation for June:

f(6) = 11(6) + 1 = 67

Note how the points on the graph seem to match up with these values. If we evaluate following the same style for each:

f(3) = 11(3) + 1 = 34

f(4) = 11(4) + 1 = 45

f(5) = 11(5) + 1 = 56

Note, these values seems to be very close in approximation to the graph points for each month.

The other three functions return values that are just to far away from what are represented in the graph.

Cheers.

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Find the volume of the figure.

jeka57 [31]

Hello from MrBillDoesMath!

Answer:

1283.3

Discussion:

Volume of figure =

volume of cone + volume of cylinder =

(1/3) Pi r^2 h + Pi r^2 h =

(1/3) Pi (7)^2* 7 + Pi (7)^2 * 6 =

Pi * 7^2 ( (1/3) *7 + 6) = => using PI is approx 22/7

(22/7) * 7^2 ( 7/3 + 6) =

(22/7)* 49 (25/3) = 1283.3

Thank you,

MrB

3 0

3 years ago

You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e

victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = $\dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}$

mean = 15.58

the standard deviation $\sigma$ = $\sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}$

the standard deviation = $\sqrt{\dfrac{(26.2 - 15.58)^2 +(27.7 - 15.58)^2 +(8.6 - 15.58)^2 + (3.8 - 15.58)^2 + (11.6 - 15.58)^2 }{5 } }$

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df at 4 and 80% confidence level, the critical value t from t table = 1.533

The Margin of Error M.O.E = $t \times \dfrac{\sigma}{\sqrt{n}}$

The Margin of Error M.O.E = $1.533 \times \dfrac{9.62297}{\sqrt{5}}$

The Margin of Error M.O.E = $1.533 \times 4.3035$

The Margin of Error M.O.E = 6.60

The Confidence interval = ( $\mu \pm M.O.E$ )

The Confidence interval = ( $\mu + M.O.E$ , $\mu - M.O.E$ )

The Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The Confidence interval = (8.98 , 22.18)

7 0

3 years ago

Given f of x equals 5 times x minus 6 for x less than 3, equals x squared for x between 3 and 5 inclusive, and equals 2 times x

konstantin123 [22]

Answer:

<em>D. 5 for x less than or equal to 4, equals 2x for x between 4 and 6 including 6, and equals 4 for x greater than 6 Domain: All real number</em>s.

Step-by-step explanation:

Find the complete diagram attached

First we need to get the derivative of the functions

For the function f(x) = 5x - 6

Using the formula

If f(x) = axⁿ

f'(x) = naxⁿ⁻¹

For the function f(x) = 5x - 6

f'(x) = 1(5)x¹⁻¹

f'(x) = 5x⁰

f'(x) = 5

For the function f(x) =x²-2

f'(x) = 2x²⁻¹

f'(x) = 2x

For the function f(x) = 4x+10

f'(x) = 1(4)x¹⁻¹

f'(x) = 4x⁰

f'(x) = 4

Get the domain

The domain is the value of the input variable x for which the functions exists. For the functions given, the domain will be on all real numbers i.e the functions will exists for any value of x on the number line.

Hence Option D is correct

7 0

3 years ago

3m+n=10<br>5m-2n=2<br>what is the answer for this one

svlad2 [7]

Answer:

m = 2

n = 4

Step-by-step explanation:

Ok so to solve this, you want to get it so there is only one variable and then solve that equation. To do this, you can start by doing:

3m + n = 10

multiply both sides by 2

6m + 2n = 20

now, in both of your equations you have 2n so you can add the two equations:

6m + 2n = 20

+ 5m - 2n = 2

11m = 22

divide both sides by 11

m = 2.

Now, plug this value into the original equation, 3m + n = 10:

3 * 2 + n = 10

6 + n = 10

subtract 6 from both sides

n = 4

6 0

3 years ago

Write an equation that expresses the following relationship. p varies jointly with the square of d and the cube of u In your equ

Veronika [31]

Answer:

$p= kd^{2}u^{3}$

Step-by-step explanation:

Using k as the constant of proportionality.

The expression that expresses the relationship : p varies jointly with the square of d and the cube of u.

Varies jointly means that p will change as 'd' and 'u' will change together with respect to their powers.

We get the expression as:

$p= kd^{2}u^{3}$

5 0

3 years ago