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cluponka [151]
4 years ago
10

I need to find the greatest common factor of

lt="40s^3t^5" align="absmiddle" class="latex-formula"> , 2s^4t^4 , and 14s^6t^6.
Please help!
Mathematics
1 answer:
solong [7]4 years ago
7 0

Answer:

\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}

Step-by-step explanation:

40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4

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Nikitich [7]
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5 0
3 years ago
Function 1: y = 4x + 5
evablogger [386]
Answer: function 1

Rate of change of function 1:
Following the format of y=mx+c, the rate of change should be m, so, the rate of change for function 1 = 4

To find the gradient (rate of change):
The two points the line passes through are (x1, y1) and (x2, y2), which in this case is (1, 6) and (3, 10)
(Doesn't matter which is which but you need to make sure that once you decide which is which, you stick to it)
To calculate the gradient, you substitute these values following (y1 - y2)/(x1 - x2)

Gradient of function 2 = (10 - 6)/(3 - 1)
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Therefore, since 4 > 2, rate of change of function 1 > rate of change of function 2.
6 0
3 years ago
Mr. Reddick has 74 total yards of red and blue felt to distribute to students in his art class. Each of his 20 students gets 2.
Mkey [24]

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Step-by-step explanation:

5 0
2 years ago
5•x+5 - (5x + 25)
sukhopar [10]
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3 0
3 years ago
Read 2 more answers
50 POINTS PLEASE HELP
Rainbow [258]

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now factor the numerator (x+3)(x-2)

now find the restriction 3x-6=0  3x=6  x=2

now factor the denominator 3(x-2)

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now cross off the (x-2)

and you are left with (x+3)/3

ANSWERS:

The restriction is X=2

The simplified fraction is (x+3)/3

7 0
3 years ago
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