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VARVARA [1.3K]
2 years ago
9

Find the midpoint of PQ with endpoints P(0, 2) and Q(6, -2). Then write an equation of the line that passes through the midpoint

and is perpendicular to
Mathematics
1 answer:
Fed [463]2 years ago
7 0

Answer:

(3,0)

Step-by-step explanation:

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A circle with a shaded sector has a circumference of 12 pi millimeters. What is the area of the shaded sector? Express the answe
valentinak56 [21]

Answer:

The answer is C. 8 mm

Step-by-step explanation:

For me, i was able to divide the 80 by 12 and get 6.667 thus i was able to round up and conclude the answer in the answer choices

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Find the length of the third side. If necessary, write in simplest radical form.
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third side is 4

Step-by-step explanation:

using Pythagoras theorem,

(√33)² + l² = 7²

33 + l² = 49

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What is the range of the data in the table?
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Not sure about this.. please help!!
Lina20 [59]

Answer:

Cube

Step-by-step explanation:

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Select the correct answer. Which point lies on the circle represented by the equation (x + 7)2 + (y − 10)2 = 132? A. (5,12) B. (
Feliz [49]

Answer:

B. (-7,-3)

Step-by-step explanation:

Given the circle: (x + 7)^2 + (y - 10)^2 = 13^2

The point (x,y) which lie on the circle are the coordinate which satisfies the given equation of the circle.

We now consider the given options.

<u>Option A (5,12)</u>

When x=5, y=12

(5 + 7)^2 + (12 - 10)^2 =12^2+2^2=148\neq 169= 13^2

<u>Option B (-7,-3)</u>

When x=-7, y=-3

(-7 + 7)^2 + (-3 - 10)^2 =0^2+(-13)^2= 169=13^2

<u>Option C (-6,-10)</u>

When x=-6, y=-10

(-6 + 7)^2 + (-10 - 10)^2 =1^2+(-20)^2=401\neq 169= 13^2

<u>Option D (6,23)</u>

When x=6, y=23

(6 + 7)^2 + (23 - 10)^2 =13^2+13^2=338\neq 169= 13^2

We can see that only (-7,-3) satisfies the equation of the circle. Thus it is the point which lies on the circle.

The correct option is B.

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2 years ago
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