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drek231 [11]
3 years ago
15

........................

Mathematics
1 answer:
Travka [436]3 years ago
5 0

Answer:

The answer is C. A square

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The 10th graders are having a bake sale to raise money for their homecoming float. If they sell c cupcakes and p cake pops at th
Tomtit [17]

The amount of money raised by the 10th graders at the bake sale using the expression 0.75•c + 0.5•p, selling 60 cupcakes and 75 cake pops is $82.5

<h3>Which method can be used to calculate the sales of the 10th graders?</h3>

The expression for the amount of money raised is <em>M </em>= 0.75•c + 0.5•p

From a similar question posted online, the amount of money raised where for example 60 cupcakes and 75 cake pops are sold is required.

Based on the equation, the selling prices are;

Cupcakes, <em>c</em> = 75¢

Cake pops, <em>p</em> = 50¢

The amount of money raised is therefore;

  • M = 0.75•c + 0.5•p

M = 0.75 × 60 + 0.5 × 75 = 82.5

Therefore;

  • The amount of money raised is <em>M </em>= $82.5

Learn more about equations here:

brainly.com/question/22688504

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4 0
1 year ago
Which equation models the rational function show in the graph
MissTica

Can't give you an answer without the graph.

3 0
3 years ago
Read 2 more answers
Can someone plz help me on dis
julia-pushkina [17]

Answer:

6cm squared

Step-by-step explanation:

1 x 2 = 2 cm

2 x 3 = 6 cm

6 cm squared

4 0
3 years ago
The first term of a sequence is 18, and the fifth term is 54. What is the common difference between each two consecutive terms?
wel

Answer:

9

Step-by-step explanation:

Sorry to lazy to type

Calculation is up

7 0
2 years ago
Read 2 more answers
Use the method of lagrange multipliers to find
Yanka [14]

Answer:

a) The function is: f(x, y) = x + y.

The constraint is: x*y = 196.

Remember that we must write the constraint as:

g(x, y) = x*y - 196 = 0

Then we have:

L(x, y, λ) = f(x, y) +  λ*g(x, y)

L(x, y,  λ) = x + y +  λ*(x*y - 196)

Now, let's compute the partial derivations, those must be zero.

dL/dx =  λ*y + 1

dL/dy =  λ*x + 1

dL/dλ = (x*y - 196)

Those must be equal to zero, then we have a system of equations:

λ*y + 1 = 0

λ*x + 1 = 0

(x*y - 196) = 0

Let's solve this, in the first equation we can isolate  λ to get:

λ = -1/y

Now we can replace this in the second equation and get;

-x/y + 1 = 0

Now let's isolate x.

x = y

Now we can replace this in the last equation, and we will get:

(x*x - 196) = 0

x^2 = 196

x = √196 = 14

then the minimum will be:

x + y = x + x = 14 + 14 = 28.

b) Now we have:

f(x) = x*y

g(x) = x + y - 196

Let's do the same as before:

L(x, y, λ) = f(x, y) +  λ*g(x, y)

L(x, y, λ) = x*y +  λ*(x + y - 196)

Now let's do the derivations:

dL/dx = y + λ

dL/dy = x + λ

dL/dλ = x + y - 196

Now we have the system of equations:

y + λ = 0

x + λ = 0

x + y - 196 = 0

To solve it, we can isolate lambda in the first equation to get:

λ = -y

Now we can replace this in the second equation:

x - y = 0

Now we can isolate x:

x = y

now we can replace that in the last equation

y + y - 196 = 0

2*y - 196 = 0

2*y = 196

y = 196/2 = 98

The maximum will be:

x*y = y*y = 98*98 = 9,604

6 0
3 years ago
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