Answer: B
Step-by-step explanation:
It's the only one that's correct.
Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
The answer is 90 units hope this helps
Answer:
the third one 10 cm, 9cm 9cm
(7.2 × 10^7) ÷ (9 × 10^4)
= (7.2 / 9) x 10^(7 - 4)
= 0.8 x 10^3
= 8 x 10^2
Answer
C. 8 × 10^2
