Question

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Answer 1

area of trapezoid with dimensions  $b_1 = 4\frac{1}{4} , b_2 = 3\frac{3}{4}, h = 2\frac{1}{2}$  is $Area =10in^2$ .

Step-by-step explanation:

We know that area of trapezoid is , area = $(\frac{a+b}{2} )h$ , where a & b are bases and h is height . We have , $b_1 = 4\frac{1}{4} , b_2 = 3\frac{3}{4}, h = 2\frac{1}{2}$ .

Area = $(\frac{a+b}{2} )h$

⇒ $Area = (\frac{a+b}{2} )h$

⇒ $Area = (\frac{b_1+b_2}{2} )h$

⇒ $Area = (\frac{4\frac{1}{4} +3\frac{3}{4}}{2} )(2\frac{1}{2} )$

⇒ $Area = (\frac{\frac{17}{4} +\frac{15}{4}}{2} )(\frac{5}{2} )$

⇒ $Area = (\frac{\frac{17+15}{4}}{2} )(\frac{5}{2} )$

⇒ $Area = (\frac{\frac{32}{4}}{2} )(\frac{5}{2} )$

⇒ $Area = (\frac{8}{2} )(\frac{5}{2} )$

⇒ $Area = (\frac{40}{4} )$

⇒ $Area =10in^2$

Therefore, area of trapezoid with dimensions  $b_1 = 4\frac{1}{4} , b_2 = 3\frac{3}{4}, h = 2\frac{1}{2}$  is $Area =10in^2$ .