PLZ NEED HELP ASAP!!!

Mathematics

1 answer:

madam [21]3 years ago

4 0

Answer:

C and D

Step-by-step explanation:

I had this same problem on my quiz

You might be interested in

What is the value of y in the equation 3(3y − 15) = 0? 5 6 7 9

mezya [45]

Y = 5
3(3y - 15) is also equal to 9y - 45, which means to find y, you have to divide 45 by 9, which is 5.

4 0

3 years ago

The three angles of a triangle are in the ratio 5:4:1. Find all the angles of the triangle.

solniwko [45]

Answer:

Step-by-step explanation:

let the first angle be 5x

second be 4x

and third be 1x

as we know that by adding all the sides of triangle we get 180°

therefore ,

5x+4x+1x=180°

10x=180°

hence ,

x=18°

first angle - 18*5 = 90°

second angle - 18*4=72°

third angle - 18°

HOPE THIS HELPS YOU !!!

6 0

3 years ago

Read 2 more answers

The prices of all college textbooks follow a bell-shaped distribution with a mean of $113 and a standard deviation of $12. Using

Soloha48 [4]

Step-by-step explanation:

In statistics, the empirical rule states that for a normally distributed random variable,

68.27% of the data lies within one standard deviation of the mean.

95.45% of the data lies within two standard deviations of the mean.

99.73% of the data lies within three standard deviations of the mean.

In mathematical notation, as shown in the figure below (for a standard normal distribution), the empirical rule is described as

$\Phi(\mu \ - \ \sigma \ \leq X \ \leq \mu \ + \ \sigma) \ = \ 0.6827 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi(\mu \ - \ 2\sigma \ \leq X \ \leq \mu \ + \ 2\sigma) \ = \ 0.9545 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi}(\mu \ - \ 3\sigma \ \leq X \ \leq \mu \ + \ 3\sigma) \ = \ 0.9973 \qquad (4 \ \text{s.f.})$

where the symbol $\Phi$ (the uppercase greek alphabet phi) is the cumulative density function of the normal distribution, $\mu$ is the mean and $\sigma$ is the standard deviation of the normal distribution defined as $N(\mu, \ \sigma)$ .

According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution $N(113, \ 12)$ ,

$\Phi(113 \ - \ 3 \ \times \ 12 \ \leq \ X \ \leq \ 113 \ + \ 3 \ \times \ 12) \ = \ 0.9973 \\ \\ \\ \-\hspace{1.75cm} \Phi(113 \ - \ 36 \ \leq \ X \ \leq \ 113 \ + \ 36) \ = \ 0.9973 \\ \\ \\ \-\hspace{3.95cm} \Phi(77 \ \leq \ X \ \leq \ 149) \ = \ 0.9973$