When any substance is being heated. Safety glasses
Answer:
Variable Where Declared
In Sub1 :
A Sub1
Y Sub1
Z Sub1
X Main
In Sub2:
A Sub2
B Sub2
Z Sub2
Y Sub1
X Main
In Sub3 :
A Sub3
X Sub3
W Sub3
Y Main
Z Main
Explanation:
In static-scoped languages with nested subprograms, the declaration of a variable is checked with the subprogram, if it is not found, it check within the parent method that called it, it continue until it find a declaration, if no declaration is found, it display an error.
In Sub1, a, y, z is declared there while the declaration of x is found in main.
In Sub2, a, b, z is declared, declaration of y is found in sub1 and declaration of x is found in main.
In Sub3, a, x, w is declared while the declaration of y, z is from the main.
Answer:
B. i < list.length
Explanation:
This question is terribly worded, but I assume the meaning is which answer will not result in an error if it's used in the while condition of the for loop. The correct answer is b. i < list.length is telling the loop to continue as long as the variable i is less than the length of the array list.
Answers C and D could potentially be valid under certain circumstances, but very unusual. Answer A will give an error as list[list.length] will give an undefined value (assuming this is indeed javascript and not some other languge).
Answer and Explanation:
"The inquiry as presented is not necessarily responsible. A word has been states as 32-bit. We need to ask if the frame is "byte-addressable" (From this we can access to get an 8-bit piece of information) or "text-addressable" (the smallest open lump is 32-bit) or maybe "half-word-addressable" (the tiny bundle of information it could reach to 16-bit).
To understand what the smallest request bit of a position is to let anyone know, you have to remember this.
You operate from base up at that stage. We will agree with the byte-addressable structure. Every reserved square at a certain point contains 8 words * (4 bytes/word) = 32 = 25 bytes, so the counterbalance seems to be 5 bits.
The history in a direct-mapped stored is the squares in reserves (12 bits for this position due to 212 = 4096). at a certain point, as you have seen, the tag is also one of the bits left behind.
As the reserve becomes increasingly cooperative. And a similar size remains. These are lesser bits on the list and more bits on the mark.'
The answer is d
letter.isdigit()
