A water tank holds 24,000 gallons.How many hours will it take for 2/3 of the water to be used if the water is used at an average
2 answers:
Answer:
590.76 hours
Step-by-step explanation:
A water tank holds 24,000 gallons
Two-Third of water quantity =
=
Rate of using water is 650 gallons per day
650 gallons of Water used in day = 1
650 gallons of Water used in hours= 24
1 gallon of Water used in hours=
16000 gallon of Water used in hours=
Hence It will take 590.76 hours for 2/3 of the water to be used
You might be interested in
Answer:
Option "3" is the correct answer to the following question:
Step-by-step explanation:
Given:
Radius of cone (r) = 6 centimeter
height of cone (h) = 8 centimeter
slant height of cone (l) = 10 centimeter
Find:
Lateral surface area of the cone = ?
Computation:
⇒ Lateral surface area of the cone = rl
⇒ Lateral surface area of the cone = (6 centimeters) (10 centimeters)
⇒ Therefore, option "3" is the correct answer.
Answer:
Mrs. B's age = y = 38 years
her son's age = x = 8 years
Step-by-step explanation:
To Find:
Mrs. B's age = y =?
her son's age = x = ?
Solution:
Let Mrs. B's age be 'y' years
and her son's age be 'x' years
Three years ago Mrs B's will be (y - 3) and her son's age will be (x - 3)
According to the first given condition,
y = 6 + 4x ...............Equation ( 1 )
According to the second given condition,
(y - 3 ) = 7 (x - 3 )..........Equation ( 2 )
equating equation 1 in equation 2 we get
6 + 4x -3 = 7x - 21
7x - 4x = 21 + 3
∴
Now substitute x in equation 1 we get
y = 6 + 4×8
y = 6 + 32
∴ y = 38 years
Mrs. B's age = y = 38 years
her son's age = x = 8 years