Question

What is the equation of the following line written in slope-intercept form?

Answer 1

B. y=2/3x-13/3 is written in slope intersept form

Answer 2

WE use given graph to find equation of the line

one point on the graph is (-5,-1)

other point on the graph is (-2,-3)

We need to frame equation y =mx+b

Lets find slope using (-5,-1) and (-2,3)

$slope m = \frac{y^2-y_1}{x_2-x_1} = \frac{-3-(-1)}{-2-(-5)} =\frac{-2}{3}$

Now we find y intercept b using (-5,-1)

y=mx+b

$-1= \frac{-2}{3}(-5) + b$

$-1= \frac{10}{3}+b$

Subtract 10/3 on both sides

$-1 - \frac{10}{3}=b$

$\frac{-13}{3}=b$

So equation of the line is $y=\frac{-2}{3}x-\frac{13}{3}$