Evaluate 11p4 and 9c5

1 answer:

7 0

$\bf _{n}P_{r}=\cfrac{n!}{(n-r)!}\qquad \qquad _{11}P_4=\cfrac{11!}{(11-4)!}
\\\\\\
_nC_r=\cfrac{n!}{r!(n-r)!}\qquad \qquad _9C_5=\cfrac{9!}{5!(9-5)!}
$

check your calculator on the factorial(!) button.

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Assuming this complete question:

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