These are two questions and two answers.
Question 1) Which of the following polar equations is equivalent to the parametric equations below?
<span>
x=t²
y=2t</span>
Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>
Explanation:
1) Polar coordinates ⇒ x = r cosθ and y = r sinθ
2) replace x and y in the parametric equations:
r cosθ = t²
r sinθ = 2t
3) work r sinθ = 2t
r sinθ/2 = t
(r sinθ / 2)² = t²
4) equal both expressions for t²
r cos θ = (r sin θ / 2 )²
5) simplify
r cos θ = r² (sin θ)² / 4
4 = r (sinθ)² / cos θ
r = 4 cosθ / (sinθ)²
r = 4 cot θ csc θ ↔ which is the option A.
Question 2) Which polar equation is equivalent to the parametric equations below?
<span>
x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>
Answer: option B) r = sinθ + 1
Explanation:
1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ
2) replace x and y in the parametric equations:
a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span>
b) r sinθ =sin²(θ)+sin(θ)</span>
3) work both equations
a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1] ⇒ r = sinθ + 1
<span>
b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
Answer:
48,217 maybe idk
Step-by-step explanation:
polynomial of the 5th degree, with two terms.
Distribute 4x^2(–2x^2 + 5x^3) to get –8x^2 + 20x^5. Reorder in standard form 20x^5-8x^4. 5 is the highest exponent so it is the 5th degree, there are two terms because terms are separated by a plus or minus.
Answer:
3/12 = 4/12
or
3/12 = 1/3
being are last boxes to autofill.
Step-by-step explanation:
1/12 +1/4 = 1/12 + 3/12 = 4.12 = 1/3
When adding the rule of fractions is where required make all denominators the same by dividing the one you want to change to- by the subset one you are changing.
12 / 4 = 3
we get 3/12
Then when adding same denominators 1/12 + 3/12 we just add the top values. = 4/12
The last box would be 4/12 but if asked to simplify we would automatically enter 1/3 for simplification.
As 4/12 = 1/3
