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Dmitry [639]
3 years ago
15

Solve for a side in right triangles (soh cah toa)

Mathematics
1 answer:
nevsk [136]3 years ago
3 0
Cos(35) = x/6
or 6 * cos(35) = x
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2. Find the Median Average of these quiz scores:<br>93, 79, 83, 89, 90, 71, 85, 93, 88, 86​
steposvetlana [31]

Answer:

90 and 71 or 80.5

Step-by-step explanation:

find middle two numbers

add them together

divide by 2

3 0
3 years ago
Read 2 more answers
A dump truck brought 1⁄3 of a ton of rock on the first trip, 1⁄2 of a ton on the second trip, but on the third trip, had to take
Allisa [31]

Answer:

1/30 of a ton

Step-by-step explanation:

Write this as an expression:

1/3 of a ton and 1/2 of a ton were taken to the site.

4/5 of a ton were remove from the site.

Amount of a ton at the site  =   \frac{1}{3}+ \frac{1}{2}- \frac{4}{5}

Solve the equation by finding <u>common denominators</u> (when the bottom numbers are the same).

(\frac{1}{3}+ \frac{1}{2})- \frac{4}{5}       Focus on the first part. The least common multiple (LCM) of 3 and 2 is "6", which will become the denominator.

For <u>1/3 to become ?/6</u>, multiply top and bottom by 2.

For <u>1/2 to become ?/6</u>, multiply top and bottom by 3.

(\frac{2}{6}+ \frac{3}{6})- \frac{4}{5}

Now we can add the numerators together over the same denominator.

\frac{5}{6}- \frac{4}{5}

Do the same thing as before and change the denominators. The LCM of 6 and 5 is "30".

For <u>5/6 to become ?/30</u>, multiply top and bottom by 5.

For <u>4/5 to become ?/30</u>, multiply top and bottom by 6.

\frac{25}{30}- \frac{24}{30}

Subtract the numerators:

\frac{1}{30}                  Answer in tons

Therefore there was 1/30 of a ton of rock left at the construction site.

7 0
3 years ago
Read 2 more answers
Given the function f(x) graphed on the coordinate plane 15
den301095 [7]

Answer:

2

Step-by-step explanation:

5 0
2 years ago
Find the value of 1/2 divide by 1/3
Hunter-Best [27]

Answer:

1.5

Step-by-step explanation:

its 1.5 not 1/5

5 0
3 years ago
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A woman in a highland village in the Andes knits sweaters and sells them for export. She also takes care of her family and helps
Mnenie [13.5K]

Answer:

Expected number of sweaters per month can be given as follows:

E(X) = Σ x P(X = x)

Now,

E(X) = [2 * 0.1 + 3* 0.1+ 4* 0.2 + 5* 0.3 + 6* 0.2 + 7 * 0.1]

E(X) = 4.7.

Var(X) = E(X^2) – [E(X)]^2

     We have E(X) = 4.7. Thus, [E(X)]2= 4.7*4.7 = 22.09.

Now E(X^2) = [2*2 * 0.1 + 3*3* 0.1+ 4*4* 0.2 + 5*5* 0.3 + 6*6* 0.2 + 7*7*0.1]

    E(X^2) = 24.1

Thus by formula, Var(X) = E(X2) – [E(X)]2

Var(X) = 24.1-22.09

Var(X) = 2.01

Given that exporter pays the $12 for each sweater. The woman pays $2 per sweater. The cost of shipment is $3 irrespective of the number of sweaters. Now, let m is the number of sweaters she made. Thus, the total cost she would have to pay would be

Total cost by woman = 2m+3

The total cost paid by the exporter would be = 12m.

Now the profit of woman would be given by,

                  = The total cost exporter pay – cost paid by the woman

                 = 12m – (2m +3)

                 = 12m – 2m -3

                 = 10m – 3.

Now expected profit made by the woman is given in the following table below:

E(Profit) = Σ profit* P(X = x)

In a similar way, as we have done in part (a).

E(Profit) = [17 * 0.1 + 27* 0.1+ 37* 0.2 + 47* 0.3 + 57* 0.2 + 67 * 0.1]

E(Profit) = 44.

Now, we calculate the variance:

Var(profit) = E(profit^2) – [E(profit)]^2

Var(profit) =

E(profit^2) = [17*17 * 0.1 + 27*27* 0.1+ 37*37* 0.2 + 47*47* 0.3 + 57*57* 0.2 + 67*67*0.1]

    E(profit^2) = 2137.

[E(profit)]^2 = 44*44 = 1936.

Thus, the variance can be given as =

Var(profit)= 2137 – 1936

Var(profit) = 201.

6 0
2 years ago
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