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3 years ago

11

There are 12 iron-on patches in 4 packages. Each package has the same number of patches. Write a rule in words for the number of

packages Leah needs to buy to get x patches. (Write an expression)

1 answer:

avanturin [10]3 years ago

5 0

12÷4 packages = can x=3 per package

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Which sequence of rigid transformations will respectively produce the images ΔA′B′C′, ΔA′′B′′C′′, and ΔA′′′B′′′C′′′ from the p

Mekhanik [1.2K]

The answer would be C. Happy mathematics!

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3 years ago

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Christen returned an overdue book to the library. Her fine

vovikov84 [41]

Answer:

Most likely 3 because the longer it is the more you pay so she couldnt have had it overdue it for too long otherwise it would be more expensive so I would say 3.

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3 years ago

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How do you solve the equation F = 9/5(K - 273.15) + 32 when you're solving for K?

Mumz [18]

$\displaystyle\\Answer:\ K=\frac{5}{9}(F-32^0)+273.15^0$

Step-by-step explanation:

$\displaystyle\\F=\frac{9}{5} (K-273.15)+32\\F-32=\frac{9}{5} (K-273.15)+32-32\\F-32=\frac{9}{5} (k-273.15)\\Multiply\ both\ parts\ of\ the\ equation\ by\ \frac{5}{9} \\(\frac{5}{9})(F-32)=\frac{9}{5} (K-273.15)(\frac{5}{9} )\\\\\frac{5}{9} (F-32)=K-273.15\\\\\frac{5}{9} (F-32)+273.15=K-273.15+273.15\\\\\frac{5}{9} (F-32)+273.15=K$

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2 years ago

What does x equal in the following equation?

saveliy_v [14]

B is the answer if it is x + 9=20

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3 years ago

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A 20-ft-long wire is used to support a television antaans. The wire is connected to the

MariettaO [177]

Answer:

The distance of base of wire to the base of tower is 13.27 ft

Step-by-step explanation:

Given as :

The measure of wire connected between base ad antenna top = 20 ft

The wire is connected to the antenna on tower at height h = 15 ft above the ground

Let The distance of base of wire to the base of tower = x ft

Let the angle drawn on ground = Ф

Now, According to question

<u>In figure AOB</u>

Sin angle = $\dfrac{\textrm perpendicular}{\textrm hypotenuse}$

i.e SinФ = $\dfrac{\textrm AB}{\textrm BO}$

Or, SinФ = $\dfrac{\textrm h}{\textrm 20}$

Or, SinФ = $\dfrac{\textrm 15}{\textrm 20}$

Or, SinФ = $\dfrac{\textrm 3}{\textrm 4}$

or, Ф = $sin^{-1}(\frac{3}{4})$

∴ Ф = 48.5°

<u>Now, Again from figure</u>

Tan angle = $\dfrac{\textrm perpendicular}{\textrm base}$

i.e TanФ = $\dfrac{\textrm AB}{\textrm OA}$

Or, Tan 48.5° = $\dfrac{\textrm h}{\textrm x}$

Or, 1.13 = $\dfrac{\textrm 15}{\textrm x}$

∴ x = $\dfrac{\textrm 15}{\textrm 1.13}$

i.e x = 13.27 feet

So, The distance of base of wire to the base of tower = x = 13.27 ft

Hence, The distance of base of wire to the base of tower is 13.27 ft Answer

5 0

4 years ago