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3 years ago

Please help me out??????

Mathematics

1 answer:

MatroZZZ [7]3 years ago

6 0

Answer:

Your answer should be 54!

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Factor this polynomial using the GCF: 3xy^2 + 3xy^2 - 3xy

Olenka [21]

3xy^2 + 3yx^2 - 3xy....GCF is 3xy

3xy(y + x - 1) <==

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3 years ago

Using GCF and the distributive property, write two equivalent expressions for 30+45?

yaroslaw [1]

5x15, 3x25 because 30+45=75 and both 5x15 and 3x25 equal 75

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3 years ago

Find the value of each variable. If your answer is not an integer, express it in simplest radical form.

Butoxors [25]

Recognize that these are isosceles right triangles, so the legs are equal and the hypotenuse is √2 times the leg length.

1. x=9, y=9√2

3. x=20, y=20√2

5 0

3 years ago

-9 is greater than a. -10 b. -7 c. -6 d. -9 e. 0

Alex_Xolod [135]

Answer:

-10

Step-by-step explanation:

On the number line -9 appear before -10. Thw futher the number, the smaller it gets

4 0

3 years ago

Need help with this math question

anastassius [24]

Answer:

The vertex is: $(6, 8)$

Step-by-step explanation:

First solve the equation for the variable y

$x^2-4y-12x+68=0$

Add 4y on both sides of the equation

$4y=x^2-4y+4y-12x+68$

$4y=x^2-12x+68$

Notice that now the equation has the general form of a parabola

$ax^2 +bx +c$

In this case

$a=1\\b=-12\\c=68$

Add $(\frac{b}{2}) ^ 2$ and subtract $(\frac{b}{2}) ^ 2$ on the right side of the equation

$(\frac{b}{2}) ^ 2=(\frac{-12}{2}) ^ 2\\\\(\frac{b}{2}) ^ 2=(-6) ^ 2\\\\(\frac{b}{2}) ^ 2=36$

$4y=(x^2-12x+36)-36+68$

Factor the expression that is inside the parentheses

$4y=(x-6)^2+32$

Divide both sides of the equality between 4

$\frac{4}{4}y=\frac{1}{4}(x-6)^2+\frac{32}{4}$

$y=\frac{1}{4}(x-6)^2+8$

For an equation of the form

$y=a(x-h)^2 +k$

the vertex is: (h, k)

In this case

$h=6\\k =8$

the vertex is: $(6, 8)$

5 0

3 years ago

Please help me out??????​

Please help me out??????