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2 years ago

5

Suppose x has a normal distribution with mean μ = 45 and standard deviation σ = 9. describe the distribution of x values for sam

ple size n = 4. (round σx to two decimal places.) μx = σx =

1 answer:

Fofino [41]2 years ago

4 0

The standard deviation of a particular sample is equal to the standard deviation divided by the square root of the sample size. That is, $\sigma_x=\frac{\sigma}{\sqrt n}$
The mean of a particular sample is equal to the mean of the set the sample was taken from. That is,
$\mu_x=\mu$
$\text{In your case, }\sigma_x=\frac{9}{\sqrt4}=\frac92\text{ and }\mu_x=45.$

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URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(c) $\log_2(\dfrac{64}{8})=3$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

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2 years ago

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The answer is the last on 12

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2 years ago

The sum of two numbers is 50 and their difference is 4 what are the two numbers

Deffense [45]

Answer:

27 and 23

Step-by-step explanation:

We can solve this problem as a system of equations. X is the first number and Y is the second number.

The first equation is x+y = 50 and the second equation is x-y=4

Now we solve the system, using elimination method:

x+y=50

x-y=4

2x = 54

x = 54/2

x = 27

And from any of the equations we can find Y

27 + y = 50

y = 50 - 27

y = 23

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2 years ago

During the spring car wash, the activities club washed 14 fewer cars than during the summer car wash. They washed a total of 96

Mashutka [201]

You can make an equation to solve this, but establishing knowns, unknowns, and relationships.

# in spring wash = x
# in summer = x + 14
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96 = 2x + 14
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"x" = 41

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