Question

Suppose x has a normal distribution with mean μ = 45 and standard deviation σ = 9. describe the distribution of x values for sample size n = 4. (round σx to two decimal places.) μx = σx =

Answer 1

The standard deviation of a particular sample is equal to the standard deviation divided by the square root of the sample size.  That is,$\sigma_x=\frac{\sigma}{\sqrt n}$
The mean of a particular sample is equal to the mean of the set the sample was taken from.  That is,
$\mu_x=\mu$
$\text{In your case, }\sigma_x=\frac{9}{\sqrt4}=\frac92\text{ and }\mu_x=45.$