Which sequences are arithmetic? Check all that apply.

One serving of a certain brand of yogurt contains 12 G of fat the low-fat version contains 38.75% less fat per serving how many

Mkey [24]

Answer:

One serving of law-fat yogurt contains 7.35 g of fat.

Step-by-step explanation:

One serving of

a certain brand of yogurt contains 12 g of fat
the low-fat yogurt contains 38.75% less fat

Let x g be the amount of fat in low-fat yogurt. Then

12 g of fat - 100%

x g of fat - 100% - 38.75% = 61.26%

Write a proportion

$\dfrac{12}{x}=\dfrac{100}{61.25}$

Cross multuply

$100\cdot x=12\cdot 61.25\\ \\100x=735\\ \\x=\dfrac{735}{100}=7.35$

One serving of law-fat yogurt contains 7.35 g of fat.

3 0

3 years ago

A car travels at 60 miles per hour. If d is the distance traveled and t is the time in hours:

erastovalidia [21]

Answer:

Step-by-step explanation:

first we will break the parts of the question down:

d= distance

t= time

function: d=t(60)

the <em>independent </em>variable is t, time, because the (distance) that the car travels <u>depends </u> on how long the car has been traveling for (time) meaning that the dependent value is distance.

A table we can create with 5 coordinate pairs is:

(time) (distance)

1 hr 60miles

2 hr 120 miles

3 hr 180 miles

4 hr 240 miles

5 hr 300 miles

(to graph the coordinate pairs, you can graph the points listed in the table. the time value represents the x value since it is the independent variable, and the y value will be the distance values since it is dependent.)

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8 0

4 years ago

Fowle Marketing Research Inc., bases charges to a client on the assumption that telephone surveys can be completed in a mean tim

sergejj [24]

Answer:

a) Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

b) $t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958$

c) $p_v =P(t_{34}>2.958)=0.0028$

d) If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.

Step-by-step explanation:

Data given and notation

The sample mean is given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And the sample deviation is:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=17$ represent the sample mean

$s=4$ represent the sample standard deviation

$n=35$ sample size

$\mu_o =15$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part a State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less or equal than 15, the system of hypothesis would be:

Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Part b Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958$

Part c P-value

The degrees of freedom are given by:

$df = n-1= 35-1=34$

Since is a right tailed test the p value would be:

$p_v =P(t_{34}>2.958)=0.0028$

Part d Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.

7 0

3 years ago

in a program designed to help patients stop smoking 232 patients were given sustained care and 84.9% of them were no longer smok

grandymaker [24]

Answer:

$z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869$

$p_v =2*P(Z>1.869)=0.0616$

If we compare the p value obtained and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .

Step-by-step explanation:

1) Data given and notation

n=232 represent the random sample taken

X represent the adults were no longer smoking after one month

$\hat p=0.849$ estimated proportion of adults were no longer smoking after one month

$p_o=0.80$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.8.:

Null hypothesis: $p=0.8$

Alternative hypothesis: $p \neq 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(Z>1.869)=0.0616$

If we compare the p value obtained and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .

6 0

4 years ago

On a number line, suppose point E has a coordinate of -4 , and EG = 13. What are the possible coordinates of point G?

Ludmilka [50]

Answer:

9 or -17

Step-by-step explanation:

Hello!

The distance can be positive or negative, as we are just counting the number of units they are apart.

To find the possible coordinates for G, we can add or subtract 13 from -4 to find the possible coordinates for G.

-4 + 13 = G1
-4 - 13 = G2
9 = G1
-17 = G2

The possible coordinates of G are 9 or -17.

7 0

1 year ago