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stira [4]
3 years ago
7

Write two possible solutions to the way inequality x< 9-5

Mathematics
1 answer:
Strike441 [17]3 years ago
8 0
-1,-2,-3,-4,-5,-6,-7,-8,-9-,-10,1,2,3,-11
You might be interested in
The nth term of a sequence is 3n+5<br> write down the 5th and 6th terms of the sequence
QveST [7]

Answer:

5th term: 20

6th term: 23

Step-by-step explanation:

T5=3n+5

T5=3(5)+5

T5=15+5

T5=20.

T6=3n+5

T6=3(6)+5

T6=18+5

T6=23

T5= 20

T6= 23

6 0
3 years ago
Find measures of each exterior angle of a regular polygon with 16 sides
Maksim231197 [3]
The measure of each exterior angle = the measure of each central angle.
each angle = 360 / 16 = 22.5
3 0
3 years ago
Read 2 more answers
Please help i am new here
DENIUS [597]

Answer: 1. 3/8-1/4=1/8

2. 3/8+1/4=5/8

3. x=5/8

Step-by-step explanation: 1. you have to subtract 3/8 by 1/4 because you have to use the largest number to subtract for the smallest number so 3/8-1/4=1/8

2. Add by adding 3/8 by 1/4 because you have to find the value of x so 3/8+1/4=5/8

3. look at number 2. and the answer is x= 5/8

plz mark me brainliest

you can mark me brainliest when 2 people answered and on my answer look on the bottom right and tap the crown. thx!

6 0
3 years ago
a sequence has a first number of 3 and a half common difference of 4 what is the recursive rule of nth term​
ELEN [110]

Answer:

f(n) = f(n-1) + 8 for n > 1

Step-by-step explanation:

Given

f(1) = 3 -- First Term

\frac{1}{2}d = 4 --- half common difference

Required

Find the recursive rule

First, we calculate the common difference

\frac{1}{2}d = 4

Multiply through by 2

2 * \frac{1}{2}d = 2 * 4

d = 8

The second term of the sequence is:

f(2) = 3 + 8 = 11

The third term is:

f(3) = 11 + 8 = 20

So, we have:

f(1) = 3

f(2) = 3 + 8

Substitute f(1) for 3

f(2) = f(1) + 8

Express 1 as 2 - 1

f(2) = f(2-1) + 8

Substitute n for 2

f(n) = f(n-1) + 8

Similarly:

f(3) = 11 + 8

Substitute f(2) for 11

f(3) = f(2) + 8

Express 2 as 3 - 1

f(3) = f(3-1) + 8

Substitute n for 3

f(n) = f(n-1) + 8

Hence, the recursive is:

f(n) = f(n-1) + 8 for n > 1

8 0
3 years ago
Can someone help me please :)
hram777 [196]
B. The fraction 4/9 is 4 times as large as 1/9
7 0
3 years ago
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